3 years ago

How to find the formula for the sum of series that is not arithmetic nor geometric?please give examples

1 answer:

8 0

Im not sure tho sorry for your inconvenience

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yan [13]

$66a^3b^3=\boxed{33a^3}\cdot2b^3\\\\99a^4=\boxed{33a^3}\cdot 3a\\\\GCF(66a^3b^3;\ 99a^4)=\boxed{33a^3}$

4 0

3 years ago

mote1985 [20]

A:23,500 seats
B and C: both have 11,750 seats

7 0

3 years ago

kirza4 [7]

Answer:70;20

Step-by-step explanation:

3 0

3 years ago

Vladimir [108]

S+9

More than suggests addition.

7 0

3 years ago

Leokris [45]

Answer:

The division will be represented as:

$\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}$

Step-by-step explanation:

1) Let's find a number with a variable that multiplied by 6x gives as 18x². It will be 3x, because (6x+5)3x=18x²+15x.

Now, let's subtstract:

$(18x^{2}-3x+4)-(18x^{2}+15x)=-18x+4$

2) Let's find a number with a variable that multiplied by 6x gives as -18x. It will be -3, because (6x+5)(-3)=-18x-15.

Now, let's subtstract:

$(-18x+4)-(-18x-15)=19$

Therefore, the division will be represented as:

$\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}$

I hope it helps you!

5 0

3 years ago