When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
A^3
a to the power of three
Answer:
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To find the decimal value, we must convert 1/2 and 3/4 into decimal.
1/2=0.5
3/4=0.75
Now we just have choose a random decimal in between the decimal.
Let's choose 0.6
Now we have to convert the decimal into a fraction. So we'll multiply the decimal by100.
0.6×100=60
Then we make the 60 into a fractions. 60/100
Then we'll simply the fraction. 60/100÷10=6/10÷2=3/5
There you go. You have your answer.
2 x 117
3 x 78
6 x 39
9 x 26
13 x 18
