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IRINA_888 [86]
2 years ago
8

What is 6×7 broken apart

Mathematics
1 answer:
Alecsey [184]2 years ago
8 0
Distrubutied (2+4)X(3+4) answer 42
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HELP HELP HELP ME YOU'LL GET 50+ BRAINLIEST POINTS PLEASE HELP ME PLEASE PLEASE ANSWER CORRECTLY PLEASE
yaroslaw [1]
The answer is 9.5 ( rounded, answer is 9.486833)
3 0
2 years ago
After prime planting season was over, a horticulturist sold lilac bushes for $15.00. If the original price was $39.00, what is t
hoa [83]
Find what percent of $39.00 the sale price was.
=> 15/39*100=38.4%
now subtract from 100% to get the mark down percentage.
100-38.4=61.6
Final answer:
Marked down 61.6%
Hope I helped :)
4 0
2 years ago
Solve for x.<br> -2-2x/3=-8<br> = [?]
VLD [36.1K]

Answer:

ml hahhahahahahaha

Step-by-step explanation:

mlhahahahahahahaha

8 0
2 years ago
Need help will give 15 points
Fantom [35]

Answer:

y = -2/3x + 6

Step-by-step explanation:

To find the slope, find how much y changes in proportion to x. Here, when x changes by 1, y changes by -2/3. So, the number before x is -2/3.

To find the y-intercept, we need to find what y will be when x is 0. Since we know that when x is 1, y is 16/3, and when x decreases by 1, y increases by 2/3. So, when x is 0, y is 16/3 + 2/3, which is 18/3, or 6.

5 0
3 years ago
Bad gums may mean a bad heart. Researchers discovered that 80% of people who have su ered a heart attack had periodontal disease
saul85 [17]

Answer:

0.069 = 6.9% probability that he or she will have a heart attack

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not have periodontal disease

Event B: Has a heart attack.

Probability of not having a periodontal disease:

100 - 80 = 20% of 10%(had a heart attack).

30% of 100-10 = 90%(did not have a heart attack). So

P(A) = 0.2*0.1 + 0.3*0.9 = 0.29

Intersection of A and B:

Not having the disease, suffering a heart attack, so 20% of 10%.

P(A cap B) = 0.2*0.1 = 0.02

What is the probability that he or she will have a heart attack?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.02}{0.29} = 0.069

0.069 = 6.9% probability that he or she will have a heart attack

6 0
3 years ago
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