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3 years ago

Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (1, 5).

Mathematics

1 answer:

Lesechka [4]3 years ago

4 0

Answer:

4x-y+1=0

Step-by-step explanation:

here,given equation of a line id

4x-y-2=0.. eqn(i)

equation of any line parallel to line (i) is

4x-y+k=0...eqn(ii)

since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]

4*1-5+k=0

or, 4-5+k=0

or,-1+k=0

•°•k=1

substituting the value of k=1 in eqn(ii),

4x-y+1=0 is the required equation of the line.

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3 years ago

Write the equation using function notation f(x). then find f(0)<br><br> 2x^2 - 3y = 6

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f(0) = -2$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6$

$\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2}$

$\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6$

$\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3}$

$\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

[ here, y can be replaced with f(x) because y is a function of x ]

$\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

$\large\textsf{Find f(0):}$

$\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2$

$\qquad \tt \rightarrow \: f(0) = 0 - 2$

$\qquad \tt \rightarrow \: f(0) = - 2$

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