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elena55 [62]
3 years ago
8

When a number is decreased by 17%, the result is 15. What is the original number to the nearest tenth?

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

About 18.1

Step-by-step explanation:

You can solve this problem by setting up an equation. Assuming that the original number is x:

x*(1-0.17)=15

0.83x=15

x=15/0.83 which is about 18.1 Hope this helps!

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College courses taken in high school for which students automatically receive both high school and college credits is called ___
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The answer is D. Dual enrollment courses

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Armand ran the 100 yard dash in 17.18 seconds. Arturo's time has an 8 with a value 10 times the value of the 8 in Armand's time.
frosja888 [35]
8====D

He has a value of 64
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3 years ago
Marta simplified this expression.
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Answer:

  • Step 1

Step-by-step explanation:

<u>Marta made a mistake at step 1</u>

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3 years ago
Perimeter of a mirror is 260. The length is x cm. Find the height of the mirror in terms of x
Elenna [48]

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4 0
3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
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