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2 years ago

9

joe received $375 for his graduation He put $205 into his savings account About what Percent of his graduation money did joe put

into savings

1 answer:

Eva8 [605]2 years ago

5 0

54%. Next time you should search "what percent is 205 of 375"

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Your teacher spent 55$ on tulips and daffodils. a pot of tulips cost 5$ and a pot of daffodils cost 4$. if your teacher bought 1

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7 tulips and 5 daffodils. An easy way to work this out is to list the multiples of both 5 and 4 until you get up to 55. Then you can find one number from each list which would add up to 55( which in this case would be 35 and 20) 35 being 7th in the 5 times table and 20 being 5th in the 4 times table.

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3 years ago

Read 2 more answers

The area of the sector of a circle with the radius of 8 cm is 125.6 sq cm the estimate value 3.14 what is the angle of the secto

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3 years ago

use benchmarks to determine the costomaryand metric units you would use to measure the height of your house. explain your answer

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What are the words? there are no words being showed.

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3 years ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

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2 years ago

1to (x204)<br> Which expression is equivalent to<br> ?

Anit [1.1K]

know is this is 64?creó piensas jdnd

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3 years ago