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3 years ago

Determine the intervals on which the function is increasing, decreasing, and constant

Mathematics

2 answers:

aleksley [76]3 years ago

4 0

Answer:

Continuously increasing

Step-by-step explanation:

Given is a graph of the function which shows a curve passing through 0, passing only in I and III quadrants.

It starts from bottom for low values of x, and slowly raise upto 0 and then again start raising.

This implies that gradient or slope of the function is positive and never negative or zero.

THis in turn implies that the curve is strictly increasing throughout its domain.

max2010maxim [7]3 years ago

3 0

I believe it's increasing on all fronts, because if you start from the right, you see that the y values always increase, hence they are increasing. They do it for when x<0 and when x>0. So, it should be increasing on all real numbers

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What times 3 equals 3/10

Mumz [18]

Answer:

1/10

Step-by-step explanation:

Divide 3/10 by 3. Remember to "keep, flip, change".

3/10 ÷ 3/1

3/10 × 1/3

Multiply across: 3/10 × 1/3 = 3/30

Simplify: 3/30 = 1/10

7 0

3 years ago

a village having a population of 4000, requires 150 litres of water per head per day. it has a tank measuring 20m x 15m x 6m. fo

allochka39001 [22]

The water will last for 3 days

Solution:

Given that, village having a population of 4000, requires 150 litres of water per head per day

Let us first find the volume of tank

The tank measuring 20m x 15m x 6m

Length = 20 m

Breadth = 15 m

Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

Thus volume of tank is 1800 cubic meter

From given,

Water required per person per day = 150 liters

Therefore, water required for 4000 people per day is:

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

$600000 \text{ liters } = 600000 \times \frac{1}{1000}\ m^3\\\\600000 \text{ liters } = 600\ m^3$

How many days will the water of this tank last?

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

Thus the water will last for 3 days

5 0

3 years ago

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

nadezda [96]

Answer:

Step-by-step explanation:

We can use the distance formula

d = sqrt ( ( y2-y1)^2 + ( x2-x1) ^2)

d = sqrt ( ( 4- -3)^2 + ( -4 -2) ^2)

= sqrt ( ( 7^2 + ( -6)^2)

= sqrt( 49+ 36)

= sqrt(85)

9.219544457

Rounding to the nearest whole number

= 9

5 0

3 years ago

Simplify the expression: w2 + 7w2 + 8w - 5 + 9 - 2w2

ololo11 [35]

<h3> $6w^2 +8w +4$ is the simplified expression</h3>

Solution:

Given that,

We have to simplify

$w^2 + 7w^2 + 8w -5+9-2w^2$

We can simplify the above expression by combining the like terms

Like terms are terms that has same variable with same exponent and same or different coefficient

From given,

$w^2 + 7w^2 + 8w -5+9-2w^2$

Group the like terms

$w^2 + 7w^2 -2w^2 + 8w - 5+9\\\\Combine\ the\ like\ terms\\\\6w^2 +8w -5+9\\\\Combine\ the\ constants\\\\6w^2 +8w +4$

Thus the given expression is simplified

4 0

3 years ago

What is the solution to the system of equations y = -x - 5 and y = 2x + 4

Delvig [45]

Answer:

(-3,-2)

Step-by-step explanation:

y = -x - 5

y = 2x + 4

plug in one of the y equations

(2x+4)= -x - 5

2x+4=-x-5

3x=-9

x= -3

plug in x to one of the y equations

y= -(-3) -5

y=3-5

y= -2

x= -3, y= -2

4 0

3 years ago