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3 years ago

Determine the intervals on which the function is increasing, decreasing, and constant

Mathematics

2 answers:

aleksley [76]3 years ago

4 0

Answer:

Continuously increasing

Step-by-step explanation:

Given is a graph of the function which shows a curve passing through 0, passing only in I and III quadrants.

It starts from bottom for low values of x, and slowly raise upto 0 and then again start raising.

This implies that gradient or slope of the function is positive and never negative or zero.

THis in turn implies that the curve is strictly increasing throughout its domain.

max2010maxim [7]3 years ago

3 0

I believe it's increasing on all fronts, because if you start from the right, you see that the y values always increase, hence they are increasing. They do it for when x<0 and when x>0. So, it should be increasing on all real numbers

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Which equation has the same solution as x^2+8x-33 =0 ?

max2010maxim [7]

Answer:

1) (x+4)2 =49

Step-by-step explanation:

x^2+8x-33 = 0 Factor this equation

(x + 11)(x - 3) = 0 Set each equation equal to 0

x = -11 and 3

Test the first equation to see if it has the same solution

(x+4)2 = 49 Simplify the parentheses

(x+4)(x+4) = 49 FOIL the equation

x^2 + 8x + 16 = 49 Subtract 49 from both sides

x^2 + 8x - 33 = 0 This is the correct solution.

3 0

3 years ago

Mr. Sanchez’s class sold snickers for 1.50 each and Mr. Kelly’s class sold bottles of fruit juice for 1.26 each. Together, the c

Anon25 [30]

Mr. Sanchez’s class sold 51 snickers and Mr. Kelly’s class sold 31 bottles of fruit juice.

Step-by-step explanation:

Step 1:

Assume x is the number of snickers sold and y is the number of fruit juices sold. It is given that both the classes sold 82 items in total. so

$x + y = 82$ , take this as equation 1.

It is also given they both earned $115.56 out of which snickers sold for $1.50 each and fruit juice sold for $1.26 each. So,

$1.50x + 1.26y = 115.56$ , take this as equation 2.

Step 2:

Now we solve these equations.

Equation 1 can also be, $y = 82 - x$ , take this as equation 3.

Substitute equation 3 in 2,

$1.50x + 1.26(82-x) = 115.56,$

$1.50x + 103.32-1.26x=115.56.$

Taking the known values to the right and keeping the unknown x values on the right, we get

$0.24x = 115.56-103.32 = 12.24$

$0.24x = 12.24, x = 51.$

Substitute this is equation 1,

$x + y = 82, y = 82 - x, y = 82 - 51 = 31.$

So Mr. Sanchez’s class sold 51 snickers and Mr. Kelly’s class sold 31 bottles of fruit juice.

4 0

3 years ago

Shiloh is doing a survey to find the time her classmates spend at the beach. She asks the following question:

belka [17]

You would expect her to gather everyone’s time being at the beach and to compare them. Also, yes it is a statistical question because they are trying to find numerical data( whoever spends the most time at the beach)

7 0

3 years ago

Graph x^2/49+y+1^2/4=1

11Alexandr11 [23.1K]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Perhaps you want a graph of ...

x^2/49 +(y +1)^2/4 = 1

This is an ellipse centered at (x, y) = (0, -1) with a major axis in the x-direction of 14, and a minor axis in the y-direction of 4.

3 0

3 years ago

Rad 18x^5y + Rad 32xy^3 - Rad 128xy

True [87]

Sqrt(18x^5y) + sqrt(32xy^3) - sqrt(128xy)
You may separate the roots to produce solvable square roots!

sqrt(9x^4)*sqrt(2xy) + sqrt(16y^2)*sqrt(2xy) - sqrt(64)*sqrt(2xy)

Simplifying makes it ...
(3x^2 + 4y - 8)*sqrt(2xy)
This should be the closest you can get to a simplified equation.

5 0

3 years ago