1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
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Answer:
x 37 y 30
Step-by-step explanation:
hopes it helps yo
Answers:
- a) Mean = 20.4
- b) New mean = 20
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Explanation:
To get the mean, we add up the scores and divide by 10 (because there are 10 scores at first)
28+13+4+12+32+22+13+22+26+32 = 204
204/10 = 20.4
The mean is 20.4
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For part b), we redo those steps shown above, but tack 16 onto the list. So we'll add up all the values (including that 16 at the end) and divide by 11 this time.
28+13+4+12+32+22+13+22+26+32+16 = 220
220/11 = 20
The new mean is 20.
The new mean is slightly smaller than the old mean. Notice how 16 is smaller than 20.4, so this new score pulls down the mean just a little bit.
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Because they are like terms that is the lowest they can go