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mr Goodwill [35]
3 years ago
8

I NEED AN MATH EXPERT ON THIS..Ill give brainless and extra points​

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
I think it’s 90% cuz it’s 45/50 therefore 90/100
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HELP<br> Solve the following systems using the elimination method.<br> 5x+2y = -16<br> 4x-2y = 16
velikii [3]

Answer:

x= 0 , y= -8

Step-by-step explanation:

Add the 2 equations together, you would get:

9x = 0

Divide both sides by 9:

x = 0/9

x=0

Substitute the value of x in one of the equations to get the value of y, I picked the first one (5x+2y = -16)

5(0) +2y = -16

0+2y = -16

2y = -16

Divide both sides by 2:

y = -8

3 0
2 years ago
Read 2 more answers
How many boxes of books can the delivery person bring up at one time?
telo118 [61]
So if the delievery man weighs 160 pounds and the books is 40 pounds. and the capacity he can carry is 950 then we have to figure out how many books a 160 can carry. 
Division: 160/40=4
950/4=237.5

i tried to answer it. unless i try one more strategy. 

Multiply: 160*40=6400
Divison: 6400/950= <span>6.73684210526
</span>try and round that huge number and figure it out. because i tried. im sorry. i hope you passed. 
5 0
3 years ago
Read 2 more answers
Help i dunno the answer to it :
Novay_Z [31]

Answer:

5 miles per hour

Step-by-step explanation:

Let the speed of Kelly is v_1 miles per hour and speed of Raul is v₂ miles per hour.

Since, speed = \frac{\text{Distance}}{\text{Time}}

Kelly took 135 minutes to cover 90 miles from New York to Philadelphia.

∵ 1 minute = \frac{1}{60} hours

∴ 135 minutes = \frac{135}{60} = \frac{9}{4} hours

v₁ = \frac{90}{\frac{9}{4}}

   = 90\times \frac{4}{9}

   = 40 miles per hour

Raul took 153 minutes to cover the same distance as Kelly,

∵ 1 minute = \frac{1}{60} hours

∴ 153 minutes = \frac{153}{60} = \frac{51}{20} hours

v₂ = \frac{90}{\frac{51}{20}}

    =90\times \frac{20}{51}                        

    = 35.29

    ≈ 35.3 miles per hours

v₁ - v₂ = 40 - 35.3

         = 4.7

         ≈ 5.0 miles per hours

Therefore, Kelly is 5 miles per hours faster than Raul.     

5 0
3 years ago
Read 2 more answers
A number cube with faces labeled from 1 to 6 was rolled 20 times. Each time the number cube was rolled, the number showing on th
denis-greek [22]

Answer:

<u></u>

  • <u>2/5 = 0.4</u>

Explanation:

The table that shows the results and the question (taken from similar question) are:

<em>Number Showing       Frequency</em>

<em>on Top Face</em>

<em>      1                                     0</em>

<em>     2                                     3</em>

<em>     3                                     3</em>

<em>     4                                     6</em>

<em>     5                                     3</em>

<em>     6                                     5</em>

<em />

<em>Based on these results, what is the experimental probability that the next time the number cube is rolled it will land with 5 or 6 showing on the top face?​ </em>

<h2 /><h2>Solution</h2><h2 />

The frequencies of each event recorded for a particular experience are named<em> experimental probabilities</em> and, in general, differ from the theoretical probabilities.

Experimental probabilities, for instance, when compared with the theoretical probabilities, may show a bias, like a loaded (unfair) die.

<em>The experimental probability that the next time the number cube is rolled it will land with 5 or 6 showing on the top face </em>is equal to the number of times the die showed a 5 or a 6 on the top face (the frequencies) divided by the number of times the experiment was performed:

  • Frequency of 5 on top face: 3
  • Frequency of 6 on top face: 5

                                                     ====

                                                        8

  • Number of times the experiment was performed: 0 + 3 + 3 + 6 + 3 + 5 = 20

Probability = 8 / 20 = 2 / 5 = 0.4 ← answer

<h2 />

8 0
3 years ago
According to the telegram which of the following description of the data are true
Luba_88 [7]

Answer:ITS THE SECOND ONE

Step-by-step

7 0
3 years ago
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