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2 years ago

1 1/6 divided by 1/12

Mathematics

2 answers:

Ad libitum [116K]2 years ago

7 0

Answer:

Step-by-step explanation:

14/12

Reil [10]2 years ago

5 0

Answer:

Step-by-step explanation:

HI have a good day

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A cell phone provider charges $120 per month. There is a 15% discount for those who also subscribe to home phone service. What p

Zepler [3.9K]

Answer: $102 per month

Step-by-step explanation:

15% off $120 means $120-(.15*$120) which is 120-18=$102. The .15 is the 15%, and 15% of 120 would be the whole multiplication.

5 0

3 years ago

Can someone help please ?

forsale [732]

Answer:

5 is the hight

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me ASAP

kherson [118]

Answer:

Step-by-step explanation:

(4.6)5=23

23=23

check if you don't believe me

8 0

3 years ago

What number "c" completes the square: x^2 - 14x + c

Vladimir79 [104]

Answer:

Step-by-step explanation:

To complete the square we use the formula:

$c=(\frac{b}{2} )^{2}$

So we can plug in 14 for b to find c.

$c=(\frac{14}{2} )^{2}\\\\c=(7 )^{2}\\c=49$

Now this equation can be factored into:

$(x-7)^{2}$

6 0

3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

2 years ago