Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
The correct answer is (C)!
Since the area of the circle is 400π, 150π/400π = 135/360.
A
coefficient = 10.50 or 15, both real numbers that qualify variables
variable = c and h
constant = 50
B
10.50h + 15c + 50
10.5 x 37 + 15 x 12 + 50
388.50 + 180 + 50 = 618.50
C
Coefficient would change from 10.50 to 11.25
<span>It is fixed until the next raise.
I hope my answer has come to your help. God bless and have a nice day ahead!</span>
![\pi \times r {}^{2} \\ 3.14 \times {283.48}^{2} =](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20r%20%7B%7D%5E%7B2%7D%20%20%5C%5C%203.14%20%5Ctimes%20%20%7B283.48%7D%5E%7B2%7D%20%20%3D%20)
252,333.258656 inches 2
I think something is wrong here
Answer: 0.0241
Step-by-step explanation:
This is solved using the probability distribution formula for random variables where the combination formula for selection is used to determine the probability of these random variables occurring. This formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where:
n = number of sampled variable which in this case = 21
r = variable outcome being determined which in this case = 5
p = probability of success of the variable which in this case = 0.31
q= 1- p = 1 - 0.31 = 0.69
P(X=5) = 21C5 × 0.31^5 × 0.69^16
P(X=5) = 0.0241