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grandymaker [24]
3 years ago
11

Can you help me please?

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0
SOLUTION:

PM = 10

RM = PM

RM = 10

Hope this helps! :)
Have a lovely day! <3
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Marat540 [252]

9514 1404 393

Answer:

  C.  168°

Step-by-step explanation:

The exterior angle at any vertex of an n-gon will be ...

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<em>Using the reasonableness test</em>

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6 0
3 years ago
The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,
juin [17]

Answer:

The width is: w(x)=4x^2

The length is l(x)=2x^2+3x+5

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

a(x)=8x^5+12x^3+20x^2

The width of the rectangle is the greatest common factor of 8x^5,  12x^3 and 20x^2

That is the width is: w(x)=4x^2

We now divide the area by the width to obtain the length of the rectangle:

l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}

This simplifies to:

l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}

l(x)=2x^2+3x+5

5 0
4 years ago
Read 2 more answers
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