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3 years ago

Please help me out with these 2 questions! Legit answers only please!

Mathematics

1 answer:

geniusboy [140]3 years ago

5 0

Answer:

1.) 12 hours 2.) She made a multiplying error in the table.

Step-by-step explanation:

1.)

First, let's find the slope of this equation:

m = 135 - 81 / 5 - 3

m = 54/2

m = 27

Therefore, the equation should be y = 27x.

Now we substitute 324 for y and solve for x:

324 = 27x

12 = x (Divided 27 on both sides.)

Therefore, someone would have to work 12 hours in order to earn $324.

2.)

For this problem, it appears Amanda has found the correct equation for her recipe. When taking a look at the table, however, it seems as though she has made a multiplying error.

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Can someone pls help me?

Ilya [14]

Answer:

$\frac{2 ln(5) }{3 ln(2) }$

Step-by-step explanation:

$log_{8}(25) = \frac{ ln(25) }{ ln(8) } = \frac{ ln( {5}^{2} ) }{ ln( {2}^{3} ) } = \frac{2 ln(5) }{3 ln(2) }$

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1 year ago

WHY must the same operation be performed on both sides of an equation?

lys-0071 [83]

Answer:When you are given a problem, the two sides are equal, so they are equally weighted. As long as you do the same thing on both sides, they remain the same weight. The only way that one side can become "more weight" on a side is if you make a math mistake, and thus the answer would not satisfy the original equation

Step-by-step explanation:looked it up... have a good day!

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3 years ago

2 Vishal is training for a race. His goal is to run 5.5 miles over three days. The distances he ran each day are shown in the ta

yawa3891 [41]

Answer:

Which table?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

Θ lies in Quadrant II . sinθ=47sinθ=47 What is the exact value of cosθ in simplified form?

Pepsi [2]

I am assuming you mean 4/7 as the sine or cosine cannot be higher than 1.

Lets find <span>θ,
</span>
θ = [sin-1](4/7) = 34.85 °

But lets take into account that this value is the equivalent in Quadrant I.

If Θ lies in Quadrant II , then θ = 180 ° - 34.85 ° = 145.15 °

So cosθ = cos (145.15) = -0.821

4 0

3 years ago