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Oksi-84 [34.3K]
3 years ago
9

Please help, will give Brainliest! Reflect this figure over the y-axis:

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

<em><u>A will be your correct answer.</u></em>

<em><u /></em>

Step-by-step explanation:

When flipping shapes over the x axis, <em>(The horizontal line)</em> the <u>x coordinates stay the same</u>, but the shape's <u>y coordinates are opposite to the original shape</u>. <em>(If the shape's y coordinates are positive, then after flipping it on the x axis, the shape's y coordinate become negative.)</em>

The only flipped shape that fits this description is<u> A. or the first answer</u>.

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lilavasa [31]

The answer is the (It’s the last two.)

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8 0
3 years ago
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Can some one help me w my math
KiRa [710]

Answer: It would be B

Step-by-step explanation:

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7 0
3 years ago
Suppose a study estimated that 62% of the residents of a community (with an
kati45 [8]

Answer:

D. 55%

Step-by-step explanation:

The error range ± 9% means that the range is 9% below 62% or 9% above 62%.

The range is:

(62% - 9%) to (62% + 9%)

53% to 71%.

The only answer between 53% and 71% is 55%.

Answers A, B, C are all greater than 71%.

5 0
4 years ago
Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.
Rudiy27

Answer:

9 ft

Step-by-step explanation:

Let's begin with the formula for the volume of a square pyramid.  If s is the base length, then the area of the base is s^2.  The volume of the pyramid is then V = (1/3)(base area)(height).  We know the volume and the base length (s), and want to find the height.  Solving V = (1/3)(base area)(height)

for height, we get:

3V = (base area)(height), or

    3V

---------------- = height

base area

Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:

               3(75 ft^3)              9 ft

height = ------------------ = ----------------- = 9 ft

                 25 ft^2                   1

3 0
3 years ago
Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth. (−2.2, 4) and (8.2, 4) (−0.8,
Studentka2010 [4]

The graph is attached.

Answer:

(-2.2, 4) and (8.2, 4)

Step-by-step explanation:

In an ellipse, there is a minor radius and a major radius.

Let major radius be = a

Let minor radius be= b

From the graph, we are given:

Major radius, a = 6

Minor radius, b = 3

Now, let's find the distance from the center to the focus using the formula:

\sqrt{a^2 - b^2}

Substituting values, we have:

= \sqrt{6^2 - 3^2}

= \sqrt{36 - 9}

= \sqrt{27} = 5.916

≈ 5.2

We can see from the graph that center coordinate is (3, 4). Therefore, the approximate locations of the foci of the ellipse would be:

(3-5.2, 4) and (3+5.2, 4)

= (-2.2, 4) and (8.2, 4)

3 0
3 years ago
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