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3 years ago

Part A: Solve the equation 7x + 3x − 18 = 6(x + 3), and show your work. (5 points)

Mathematics

2 answers:

Levart [38]3 years ago

7 0

Answer:

Step-by-step explanation:

7x +3x - 18 =6(x +3)

10x - 18 =6x +18

10x - 6x =18 +18

4x =36

x=36 :4

x=9

const2013 [10]3 years ago

7 0

Answer:

$7x \: + 3x \: - 18 = 6(x + 3) \\ 10x - 18 = 6x + 18 \\ 10x - 18 + 18 = 6x + 18 + 18 \\ 10x = 6x + 36 \\ 10x - 6x \: = 6x - 6x + 36 \\ 4x = 36 \\ we \: divide \: both \: sides \: by \: 4 \\ 4x \div 4 = 36 \div 4 \\ x = 9$

hope that will help you

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How do i solve this equation

MakcuM [25]

For the first one, it would be 104-14+=x. I'm not sure about the second one, though. Sorry!

3 0

3 years ago

The prime and composite numbers of 9, 15,19,26,33,37,45,47

Elanso [62]

Prime= 19, 37, and 47
Composite= 9, 15, 26, 33, and 45
Hope this helps!

4 0

3 years ago

14. If P(A) = 0.4 and P(B) = 0.5 and P(A and B) = 0.2, then P(B|A) =

Vadim26 [7]

Answer:

14) b) P(B/A) = 0.50

15) P(A or B) = 0.7

Step-by-step explanation:

14)

Given P(A) = 0.4 and P(B) = 0.5 and P(A and B) = 0.2

Conditional probability of B given that A

$P(\frac{B}{A} ) = \frac{P(AnB)}{P(A)} = \frac{0.2}{0.4} = 0.50$

15)

By using Addition theorem on probability

P( A ∪ B) = P(A) + P(B) - P(A∩B)

= 0.4 +0.5 - 0.2

P( A ∪ B) =0.7

3 0

3 years ago

X 5 X6 7 8 A garden table and a bench cost $659 combined. The garden table costs $91 less than the bench. What is the cost of th

Greeley [361]

Answer:

The bench was $375 and the garden table was $284.

Step-by-step explanation:

Let x be the value of the bench, if the table is 91 less than the value of the bench then the equation can be:

x + x-91 = 659

2x -91 = 659

Add 91 to both sides of the equation to isolate the 2x:

2x - 91 + 91 = 659 + 91

2x = 750

Divide both sides by 2 to get 1x:

2x ÷ 2 = 750 ÷ 2

x = 375

This means the bench was $375 and the garden table was $284.

Hope this helps!

8 0

3 years ago

Graph f(x) = (1/3)^x+1

e-lub [12.9K]

Answer:

The graph is attached below.

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(1/3\right)^x+1$

Exponentiation function have a horizontal Asymptotes.

Finding the horizontal Asymptotes

$\mathrm{Exponential\:function\:of\:the\:form}\:f\left(x\right)\:=c\cdot \:n^{ax+b}+k\:$

$\mathrm{has\:a\:horizontal\:asymptote}\:y=k\:$

$k=1$

$\mathrm{The\:horizontal\:asymptote\:is:}$

$y=1$

Finding y-intercepts

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

$y=\left(\frac{1}{3}\right)^0+1$

$\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0$

$\left(\frac{1}{3}\right)^0=1$

$y=1+1$

$\mathrm{Add\:the\:numbers:}\:1+1=2$

$y=2$

$\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)$

The graph is attached below.

4 0

2 years ago