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sasho [114]
3 years ago
9

A student drove to the university from her home and noted that the odometer reading of her car increased by 16.0 km. The trip to

ok 20.0 min.?
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

Average speed is 48 km per hour

Step-by-step explanation:

A student drove to the university from her home and noted that the odometer reading of her car increased by 16.0 km. The trip took 20.0 min. (a) What was her average speed? in km/hr

Distance traveled is 16 km and the time taken is 20 minutes

convert minutes into hour. to convert minutes into hour we divide by 60 because 1 hour = 60 minutes

\frac{20}{60} =\frac{1}{3}

so time = 1/3  and distance = 16

Average speed = distance by time

speed =\frac{16}{\frac{1}{3} } =\frac{48}{1}= 48

Average speed is 48 km per hour

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
una ventana rectangular tiene l metros de ancho y h metros de altura, con un perímetro de 6 metros y un área de 2m² ¿cuál es la
seropon [69]

Answer:

The formula for calculating the width of the window is

w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}

Step-by-step explanation:

<u><em>The question in English is</em></u>

A rectangular window is l meters wide and h meters high, with a perimeter of 6 meters and an area of 2m². What is the formula for calculating the width of the window?

we know that

The perimeter of the window is equal to

P=2(l+w)

we have

P=6\ m

so

6=2(l+w)

simplify

3=(l+w)

isolate the variable l

l=3-w ----> equation A

The area of the window is equal to

A=lw

we have

A=2\ m^2

so

2=lw ----> equation B

substitute equation A in equation B

2=(3-w)w

solve for w

2=3w-w^2

w^2-3w+2=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

w^2-3w+2=0

so

a=1\\b=-3\\c=2

substitute in the formula

w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}  --->  formula for calculating the width of the window

w=\frac{3(+/-)\sqrt{1}} {2}

w=\frac{3(+/-)1} {2}

w=\frac{3(+)1} {2}=2\ m

w=\frac{3(-)1} {2}=1\ m

7 0
3 years ago
Need to draw an area model to multiply 3x31
Luda [366]
You would do three square in length and 31 in width
6 0
3 years ago
I WILL GIVE BRAINLIEST
Tom [10]

Step-by-step explanation:

9/8 × (-7/3) =

9 × -7 = -63

8 × 3 = 24

-63/24 simplify

-21/8

7 0
3 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
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