Question

Solve the system of linear equations below. x − 3y = -3 x + 3y = 9 A. x = -12, y = 7 B. x = 3, y = 2 C. x = 6, y = 1 D. x = 6, y = 2

Answer 1

ANSWER

B. x=3,y=2

EXPLANATION

The given equations are

$x - 3y = - 3...(1)$

and

$x + 3y = 9...(2)$

We add the two equations to eliminate y.

This implies that that:

$x + x - 3y + 3y = 9 + - 3$

Simplify:

$2x = 6$

Divide both sides by 2.

$x = 3$

We put x=3 into any of the equations to find y.

Let us substitute x=3 into equation (1) to get:

$3 - 3y = - 3$

$- 3y = - 3 - 3$

$- 3y = - 6$

Divide both sides by -3 to get;

$y = 2$

The solution is therefore x=,y=2.