The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
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It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
37.5 km is equal to 15 cm
Answer:
x= 3/5 or x= 0.6
Step-by-step explanation:
It says it’s 5 points not 10 points!
Answer:
the force that must be applied by the driver to release the clutch is 21 lb
Step-by-step explanation:
Data provided:
clutch linkage on a vehicle has an overall advantage = 24:1
Applied force by the pressure plate = 504 lb
Now,
the advantage ratio is given as:
advantage ratio = 
on substituting the respective values, we get
= 
or
Force applied by the driver to release the clutch = 
or
Force applied by the driver to release the clutch = 21 lb
Hence,
the force that must be applied by the driver to release the clutch is 21 lb
