Answer:
YES
Step-by-step explanation:
Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.
Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.
Substitute ⁵/4 in y = kx
We would have:
y = ⁵/4x.
Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.
Let's plug in (16, 20) into y = ⁵/4x.
Thus substitute x = 16 and y = 20, we have:
[tex] 20 = \frac{5}{4}(16) [/trex]
[tex] 20 = (5)(4) [/trex]
[tex] 20 = 20 [/trex]
It makes the equation true. Therefore, the point, (16, 20) is a point on line l.
The answer is 13.76 meters squared.
Answer:
This line is a horizontal line, so it has an equation y=n, where n is a number.
In this case, because the y intercept is (0,2) the equation is y=2.
Let me know if this helps!
Answer:
x = - 10
Step-by-step explanation:
Express the fractions on the left side as a single fraction.
Multiply the numerator/denominator of the first fraction by (x - 2)
Multiply the numerator/denominator of the second fraction by (x + 1)
+ 
= 3
Distribute the numerators and simplify
= 3 ( cross- multiply )
3x² - 2x + 4 = 3(x+ 1)(x - 2) ← distribute
3x² - 2x + 4 = 3(x² - x - 2)
3x² - 2x + 4 = 3x² - 3x - 6 ( subtract 3x² - 3x from both sides )
x + 4 = - 6 ( subtract 4 from both sides )
x = - 10
Answer:
22.9%
Step-by-step explanation:
