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Degger [83]
2 years ago
14

The distance from the center of an archery target to the outside edge of the target is 24 in. What is the diameter of the target

?
Mathematics
1 answer:
klemol [59]2 years ago
7 0

Answer:

The diameter of the target is 48\ in

Step-by-step explanation:

we know that

In this problem the  distance from the center of an archery target to the outside edge of the target is equal to the radius of the target

so

r=24\ in

Remember that

The diameter is two times the radius

D=2r

substitute

D=2(24)=48\ in

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Can someone help me with this question?
belka [17]

Answer:

The required probability is 0.0155.

Step-by-step explanation:

We are given that the one-year survival rate for pancreatic cancer is 20%.

Of 12 people diagnosed with pancreatic cancer at one hospital, 6 survived one year.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 12 people

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            p = probability of success which in our question is probability of

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Let X = <u><em>Number of people survived one year</em></u>

So, X ~ Binom(n = 12 , p = 0.20)

Now, the probability that 6 survived one year is given by = P(X = 6)

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Answer:

40

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