The distance from the center of an archery target to the outside edge of the target is 24 in. What is the diameter of the target
1 answer:
You might be interested in
In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: 
where
is the monthly payment
is the amount
is the interest rate in decimal form
is the number years
First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
We also know from our question that
and 
, so lets replace those values into our formula to find the monthly payment:
We can conclude that the monthly payment during the initial period is $1071.58<span />
where
First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
We also know from our question that
We can conclude that the monthly payment during the initial period is $1071.58<span />
Answer:
Step-by-step explanation:
We can use either angle, but I'm going to use the one on the bottom. So, in order to find x, we need to use tangent. One side we know is the adjacent, and the side we don't know is the opposite, therefore we need tangent. Here's the equation:
Obviously, we can't have a root in our denominator, so we need to get rid of it somehow. Here's how:
We multiply the denominator of the fraction by .
multiplied by itself is simply 2. Try it! We also want to multiply the numerator by
, but there isn't really a number we can use with that, so we'll just add it to the side. The equation you have now is:
Let's try to work this out now. Since the denominator is 2, we have to multiply both sides by it to find x.
We can plug 2 in for the x in the numerator now:
2 and 2 cancel out, so you get 1 in both the numerator and denominator. That's how we get our answer of
Also, because this is a 45-45-90 triangle, you don't really have to do all that work. If it's a 45-45-90 triangle, both legs should be the same length. :)
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
