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3 years ago

Which of the following shows a relationship of 4,000 as ten times greater than 400?

Mathematics

1 answer:

stira [4]3 years ago

8 0

400 times ten because when you multiply you get 40,000.

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¿Can i get the answer?

NikAS [45]

Answer:

15.7

Step-by-step explanation:

5 x 3.14(pi) = 15.7

3 0

3 years ago

What is 0.6 as a fraction in simplest form

Illusion [34]

we know that

step 1

multiply $0.6$ by $\frac{10}{10}$

$0.6*\frac{10}{10} =\frac{6}{10}$

step 2

Divide numerator and denominator by $2$

$\frac{\frac{6}{2}}{\frac{10}{2}} =\frac{3}{5}$

therefore

the answer is

$\frac{3}{5}$

4 0

3 years ago

Read 2 more answers

Pls tell me the answer with an explanation how you got it!

Flura [38]

Answer:

25 degrees

Step-by-step explanation:

40 + 50 = 90

2 x 25 = 5

8 0

3 years ago

Which functions have an axis of symmetry of x = -2? Check all that apply. A. f(x) = x^2 + 4x + 3 B. f(x) = x^2 - 4x - 5 C. f(x)

Snowcat [4.5K]

Answer:

A. f(x) = x^2 + 4x + 3

D. f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

The axis of symmetry is found by h = -b/2a where ax^2 +bx +c

A. f(x) = x^2 + 4x + 3

h = -4/2*1 = -2 x=-2

B. f(x) = x^2 - 4x - 5

h = - -4/2*1 = 4/2 =2 x=2 not -2

C. f(x) = x^2 + 6x + 2

h = -6/2*1 = -3/2 = x=-3/2 not -2

D. f(x) = -2x^2 - 8x + 1

h = - -8/2*-2 = 8/-4 =-2 x=-2

E. f(x) = -2x^2 + 8x - 2

h = - 8/2*-2 = -8/-4 =2 x=2 not -2

7 0

3 years ago

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$

So, the value of the function is minimum at $r=1.05$

$h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12$

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3$

The minimum surface area is $20.91\ \text{ft}^3$ .

8 0

3 years ago