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victus00 [196]
3 years ago
9

Logan genetically engineered a new type of fir tree and a new type of pine tree. The combined height of one fir tree and one pin

e tree is 2121 21 meters. The height of 44 4 fir trees stacked on top of each other is 2424 24 meters taller than one pine tree. How tall are the types of trees that Logan genetically engineered?
Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer: The height of  fir tree is 9 meters and the height of pine tree is 12 meters.

Step-by-step explanation:

Given : The combined height of one fir tree and one pine tree = 21 meters.

Since, the height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Let x be the height of fir tree and y be the height of pine tree.

Then we get the following equations:

x+y=21...............(1)\\4x-y=24.........(2)

Adding (1) and (2) we get

5x=45\\\Rightarrow\ x=9

Substitute the value of x in (1), we get

9+y=21\\\Rightarrow\ y=21-9=12

Hence, the height of  fir tree is 9 meters and the height of pine tree is 12 meters.

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What divided by 3 equals 24? In other words, you have an unknown number (X), and then if you divide that X by 3 you get 24. Then what is that X?

The equation to calculate what divided by 3 equals 24 is as follows:

X/3 = 24

Where X is the answer. When we solve the equation by multiplying each side by 3, you get get:

X = 72

Therefore, the answer to what divided by 3 equals 24 is 72.

Hope that helps
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3 years ago
Which set Paris does not show y as a function of x?​
Alex17521 [72]

Answer:

c

Step-by-step explanation:

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3 years ago
There are 10 rolls of film in a box and 3 are defective. two rolls are selected without replacement. what is the probability of
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P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9


P(1 and 2  defective) = 3/10 x 2/9  = 6/90 = 0.066

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 ³C₂ / ¹⁰C₂ = 1/15 = 0.066
4 0
3 years ago
PLEASE HELP IMMEDIATELY!!
Inga [223]

Answer:

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Step-by-step explanation:

6 0
2 years ago
The game of European roulette slots: 18 red, 18 black, and I green. A ball is spun onto the wheel and will eventually land ina s
Anestetic [448]

Answer:

(a) E(x) = -0.081  S.D = 3

(b) E(x) = -0.081  S.D = 1.73

(c) it is less risky to bet $1 in three different rounds as compared to betting $3 in a single round.    

Step-by-step explanation:

(a) You bet $3 on a single round which means that if you win the game, your amount will double ($6), your profit will be $3. Whereas, if you lose the round, your profit will be -$3. You can only bet on red or black and both have 18 slots each.

So, the probability of landing the ball in a red/black slot = 18/37. This is the probability of winning. The probability of losing can be calculated as 1-18/37 = 19/37.

We can make a probability distribution table:

x                    3             -3

P(X=x)         18/37      19/37

Expected value E(x) can be calculated as:

E(x) = ∑ x.P(x)

      = (3)(18/37) + (-3)(19/37)

E(x) = -0.081

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (3)²(18/37) + (-3)²(19/37)

       = (9)(18/37) + (9)(19/37)

E(x²) = 9

Var(x) = E(x²) - E(x)²

         = 9 - (-0.081)²

Var(x) = 8.993

S.D = √8.993

S.D = 2.99 ≅ 3

(b) Now, the betting price is $1 and 3 rounds are played. We will compute the expectation for one round and then add it thrice to find the expectation for three rounds. Similarly, for the standard deviations, we will add the individual variances and then consider the square root of it.

E(x) = ∑ x.P(x)

      = (1)(18/37) + (-1)(19/37)

E(x) = -0.027

Standard deviation can be calculated by the following formula:

Var(x) = E(x²) - E(x)²

S.D = √Var(x)

We need to first calculate E(x²).

E(x²) = ∑x².P(x)

       = (1)²(18/37) + (-1)²(19/37)

       = (1)(18/37) + (1)(19/37)

E(x²) = 1

Var(x) = E(x²) - E(x)²

         = 1 - (-0.027)²

Var(x) = 0.9992

The expectation for one round is -0.027

For three rounds,

E(x₁ + x₂ + x₃) = E(x₁) + E(x₂) + E(x₃)

                     = (-0.027) + (-0.027) + (-0.027)

E(x₁ + x₂ + x₃) = -0.081

Similarly, the variance for one round is 0.9992.

Var (x₁ + x₂ + x₃) = Var(x₁) + Var(x₂) + Var(x₃)

                           = 0.9992 + 0.9992 + 0.9992

Var (x₁ + x₂ + x₃) = 2.9976

S.D = √2.9976

S.D = 1.73              

(c) The expected values for both part (a) and (b) are the same but the standard deviation is lower in part (c) as compared to (b). Since the standard deviation is less in part (c), it means that it is <u>less risky to bet $1 in three different rounds as compared to betting $3 in a single round.</u>            

5 0
3 years ago
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