Question

Is this correct ? .......................

Answer 1

To find the midpoint of the two points (x₁ ,y₁) and (x₂, y₂) we need to use the formula:

$\sf{Midpoint=(\frac{x_1 + x_2}{2}, \frac{y_1+y_2}{2})}$

So to find the midpoint of E (a,a) and F (3a, a), let's plug it in to the formula:

$\sf{Midpoint=(\frac{a + 3a}{2}, \frac{a+a}{2})}$

Simplify the numerator:

$\sf{Midpoint=(\frac{4a}{2}, \frac{2a}{2})}$

Simplifying the fractions more:

$\sf{Midpoint=(2a, a)}$


So the midpoint of EF is (2a,a).

Your answer of (a,a) would be wrong.