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3 years ago

Is this correct ? .......................

Mathematics

1 answer:

ladessa [460]3 years ago

5 0

To find the midpoint of the two points (x₁ ,y₁) and (x₂, y₂) we need to use the formula:

$\sf{Midpoint=(\frac{x_1 + x_2}{2}, \frac{y_1+y_2}{2})}$

So to find the midpoint of E (a,a) and F (3a, a), let's plug it in to the formula:

$\sf{Midpoint=(\frac{a + 3a}{2}, \frac{a+a}{2})}$

Simplify the numerator:

$\sf{Midpoint=(\frac{4a}{2}, \frac{2a}{2})}$

Simplifying the fractions more:

$\sf{Midpoint=(2a, a)}$

So the midpoint of EF is (2a,a).

Your answer of (a,a) would be wrong.

You might be interested in

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

3-(-6/7)(3/8) what will it equal?

kompoz [17]

This is equals 3 and 18/56 which reduces to 3 and 9/28 all you have to do is plug it the calculator like it is shown and then you will get this answer

4 0

3 years ago

Date:

Nadusha1986 [10]

Answer:

#3 1/6, 1/6, 1/2, 1/3, 5/6.

#4 3/12, 4/12, 5/12, 8/12, 9/12

Step-by-step explanation:

#3 is numbers out of six (fractions).

#4 is the same thing. You add all of the numbers (4, 3, and 5) to get the total and then you subtract to get the probability.

These are all I know.

7 0