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baherus [9]
3 years ago
9

Find the gcf of 15a and 28b^2. 9ab^2 0 3 1

Mathematics
1 answer:
lions [1.4K]3 years ago
5 0
Answer:

GCF(15a; 28b²) = 1
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The Statistical Abstract of the United States published by the U.S. Census Bureau reports that the average annual consumption of
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Answer:

a) P(\bar X

b)P(98

c) P(\bar X

d) P(93

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(99.9,30)  

Where \mu=99.9 and \sigma=30

We select a random sample of n=36. And from the central limit theorem we know that the distribution for the sample is given by:

\bar X \sim N(\mu =99.9 , \frac{\sigma}{\sqrt{n}}= \frac{30}{\sqrt{38}}=4.87)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X

=P(Z

Part b

For this case we want this probability:

P(98

=P(\frac{98-99.9}{\frac{30}{\sqrt{38}}}

And we can find this probability on this way:

P(-0.39

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.39

Part c

If we apply this formula to our probability we got this:

P(\bar X

P(\bar X

Part d

For this case we want this probability:

P(93

=P(\frac{93-99.9}{\frac{30}{\sqrt{38}}}

And we can find this probability on this way:

P(-1.42

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.42

3 0
3 years ago
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