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Nuetrik [128]
3 years ago
9

Quadrilateral ABCD is reflected over line y as shown, resulting in quadrilateral TURS. If AD 5 in., AB = 7 in., DC = 4 in., and

BC = 9 in., what is TU? 4 in. 5 in. 7 in. 9 in.
Mathematics
2 answers:
inn [45]3 years ago
7 0



Answer:  7 inches.

Given that there was a quadrilateral ABCD and it was reflected over a line y

Hence preimage = ABCD and image = TURS

When reflected we have new position of A = T

new position of B =U

new position of C = R and

new position of D = S

By transformation properties, for reflection the scale factor is 1 and hence AB will have the same length as TU

Since AB = 7 inches, TU = 7 inches.

Note:

A reflection in the coordinate plane is just like a reflection in a mirror. Any point or shape can be reflected across the x-axis, the y-axis, or any other line, invisible or visible. This line, about which the object is reflected, is called the “line of symmetry.”  Here we have line of symmetry as line y.


SCORPION-xisa [38]3 years ago
5 0

The answer is 7 in. Just took the test and got it right. Hope this was helpful!

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Two consecutive positive integers have a
Vlad [161]

Answer:

3, 4

Step-by-step explanation:

x(x+1)=12

x^2+x-12=0

a=1, b=1, c=-12 in the quadratic formula

quadratic formula: ax^2+bx+c = 0

quadratic equation: x=(-b +/- √(b^2-4ac))   / 2a

= (-1 +/- √49 ) / 2

(-1 +/- 7) / 2

x= -4, x=3

-4 doesn't work because it is not positive

Therefore: Answer = 3, 4

4 0
3 years ago
Whats nine and eight four hundredths in standard from
Nookie1986 [14]
Do you mean 'nine and eighty four hundredths' in standard form? If so, it will be:

9.84
7 0
4 years ago
The weight of Jane and Jessica was in the ratio of 8 : 9. Jane gained 2 kg while Jessica lost 4 kg. They then had the same weigh
postnew [5]

Answer:

  48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

__

<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

  x/y = 8/9

After the changes in weight, they were equal:

  x+2 = y-4

__

<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

  y = x +6 . . . . . . . . . . solve the second equation for y

  x/(x+6) = 8/9 . . . . . . substitute for y in the first equation

  9x = 8(x +6) . . . . . . . multiply by 9(x+6)

  x = 48 . . . . . . . . . . . simplify and subtract 8x

Jane weighed 48 kg at first.

_____

<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)

3 0
2 years ago
Maria and Javier are taking a trip to a crafts store to buy supplies for an arts project. Maria buy 11 packs of ribbon and 16 ne
Umnica [9.8K]

Answer:

  • ribbon: $0.45
  • markers: $0.08

Step-by-step explanation:

Each purchase will be the sum of products of item price and number of items. The two purchases give rise to two equations.

__

<h3>equations</h3>

The variables are defined in the problem statement. The two purchases are ...

  11r +16m = 6.23

  13r +7m = 6.41

__

<h3>solution</h3>

A calculator offers a simple way to find the solutions to these equations. The attachments show the solution to be ...

  • r = 0.48
  • m = 0.08

The cost of ribbon is $0.45; the cost of a marker is $0.08.

__

The "cross-multiplication" method of solving these equations seems particularly useful when the coefficients are mutually prime. It starts with a rewrite to general form:

  • 11r +16m -6.23 = 0
  • 13r +7m -6.41 = 0

Then we define three "cross products":

Δ1 = (11)(7) -(13)(16) = -131

Δ2 = (16)(-6.41) -(7)(-623) = -58.95

Δ3 = (-6.23)(13) -(-6.41)(11) = -10.48

The solutions are ...

  r = Δ2/Δ1 = -58.95/-131 = 0.45

  m = Δ3/Δ1 = -10.48/-131 = 0.08

The cost of ribbon is $0.45; the cost of a marker is $0.08.

_____

For more about the cross-multiplication method you can read ...

brainly.com/question/26397343

5 0
2 years ago
Part A: Abe rented a bike at $36 for 5 days. If he rents the same bike for 8 days, he has to pay a total rent of $48.
lawyer [7]
(5,36)(8,48)
slope = (48 - 36) / (8 - 5) = 12/3 = 4

y = mx + b
slope(m) = 4
(5,36)...x = 5 and y = 36
now sub and find b
36 = 4(5) + b
36 = 20 + b
36 - 20 = b
16 = b

equation is : y = 4x + 16.....in standard form : 4x - y = -16 <==
=======================
function notation : f(x) = 4x + 16
=======================
x axis will be ur hrs....I would label them at intervals of 1
y axis will be total cost of renting the bike......as far as the intervals...not sure how to label them.....sorry....I wanna say intervals of 2...but am not sure

y = 4x + 16
slope = 4
y int = (0,16)
x int = (-4,0)

so start at (-4,0)....and since ur slope is 4, go up 4 and to the right 1...keep doing this and u will cross the y axis at (0,16)
7 0
4 years ago
Read 2 more answers
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