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Vlada [557]
4 years ago
11

The function f(x) and g(x) are described using the following equation and table: f(x)=-4(1.09)^x

Mathematics
1 answer:
Kryger [21]4 years ago
8 0

Answer:

The y-intercept of f(x) is equal to the y-intercept of g(x)

Step-by-step explanation:

The y-intercept of a function is the value of the function (the value of y) when x = 0. So, it is the value of y at which the function touches the y-axis.

Here we have two functions. The first function is:

f(x)=-4(1.09)^x

In order to find its y-intercept, we have to substitute x = 0 into the function and see the output. Doing so, we get:

f(0)=-4(1.09)^0=-4\cdot 1 = -4

The second function that we have instead is given by the table:

x -4 -2 0 2

g(x) -10 -7 -4 1

In order to find its y-intercept, we look at the table and we see the value of g(x) when x = 0. This is given by the 3rd point: when x = 0, then

g(0)=-4

So the correct answer is

The y-intercept of f(x) is equal to the y-intercept of g(x)

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Genrish500 [490]

Answer:

The perimeter of the hexagon is equal to 36 units

Step-by-step explanation:

Let

x-------> the length side of the hexagon

L-----> the length of the rectangle

W-----> the width of the rectangle

we know that the perimeter of the hexagon is equal to the perimeter of the rectangle is equal to so

-------> equation A

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Substitute equation B and equation C in equation A

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3 years ago
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Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos
Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$ P_{1} = (- 1, 4) $

$ P_{2} = (6, 2) $    and

$ P_{3} = (4, - 5) $

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $ (x_1, y_1) $ and $ (x_2, y_2) $ is:

                                 $ \sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+}   \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}} $

Length between $ P_1 $ and $ P_{2} $ , (Side 1) :

$ (x_1, y_1) = (- 1, 4) $     and

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2 $

$ = \sqrt{7^2 + 2^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53}} $

Length of Side 1 = $  \sqrt{\textbf{53}} $ units.

Distance between $ P_1 $ and P_2 , (Side 2):

$ (x_1, y_1) = (-1, 4) $

$ (x_2, y_2) = (4, - 5) $

Distance = $ \sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2 $

$ = \sqrt{ 25 + 81 } $

$ = \sqrt{\textbf{106}} $

Length of Side 2 = $ \sqrt{\textbf{106}} $ units.

Distance between $ P_2 $ and $ P_3 $ , Side 3 :

$ (x_1, y_1) = (4, 5) $

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53} $

Length of Side 3  = $ \sqrt{\textbf{53}} $ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$ \bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2 $

i.e, 53 + 53  = 106

Hence, the triangle is a right - angled triangle as well.

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Step-by-step explanation:

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