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Reika [66]
3 years ago
15

Select all input values for which g(x)=8

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

a. x = -4

c. x = 9

Step-by-step explanation:

Values of g(x), output values, are plotted on the y-axis, while the corresponding x values, input, of the function are plotted on the x-axis.

We are to determine all possible input values (x-values) that will give us an output value, g(x) = 8.

On the graph, look at the point where y = 8, on the y-axis. When y = 8, we have two possible values of x. They are -4, and 9.

Thus:

g(-4) = 8

g(9) = 8.

The possible input values for which g(x) = 8, are x = -4, and x = 9.

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Simplify -2.8f+0.9f-12-4
bogdanovich [222]

Answer:

  • -1.9f - 16

Step-by-step explanation:

  • -2.8f + 0.9f - 12 - 4 =
  • (-2.8 + 0.9)f - (12 + 4) =
  • -1.9f - 16
3 0
3 years ago
Read 2 more answers
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Serjik [45]
90° : )




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8 0
3 years ago
147.1 is what percent of 155
Harrizon [31]
Solution for what is 147.1% of 155

155/x=100/147.1
(155/x)*x=(100/147.1)*x       - we multiply both sides of the equation by x
155=0.67980965329708*x       - we divide both sides of the equation by (0.67980965329708) to get x
155/0.67980965329708=x 
228.005=x 
x=228.005

now we have: 
147.1% of 155=228.005

3 0
3 years ago
(3,1)(2,0)(1,-1)(3,2)(2,1)(1,0) A: Function OB: Not a function​
levacccp [35]

Answer:

Not a function

Step-by-step explanation:

Y values can repeat in a function but domain cannot. 3 is repeated twice, thus these values do not represent a function.

4 0
3 years ago
From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin
borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

8 0
3 years ago
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