So, if the <span>number is between -3 and 3, It couldn't be more than 3, so C isn't the answer. It also doesn't have to be equal to 3.
B, </span><span>|x| < 3, would be your answer.
Hope this helps!</span>
7x-2(x+1)=6x+14
7x-2x-2=6x+14
5x-6x=14+2
-x=16
x=-16
Step-by-step explanation:
5x^2+2x=1
5x^2+2x-1=0
x=-b+/-√b^2-4ac÷2a
x=-2+/-√-2^2-(4×5×-1)÷2×5
x=-2+/+√4--20÷10
x=-2+/-√24÷10
x=-2+√24÷10 or -2-√24÷10
x=-2+4.9÷10 or -2-4.9÷10
x=2.9÷10 or -6.9÷10
x=0.29 or -0.69
9514 1404 393
Answer:
(b) (x – 4)^2 + (y – 6)^2 = 16
Step-by-step explanation:
The equation for a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
You want the equation for a circle with center (4, 6) and radius 4. That equation is ...
(x -4)^2 +(y -6)^2 = 16
By definition, we have

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:
Suppose that 
In this case, the absolute value doesn't do anything: the equation is

We are supposing
, so we can accept this solution.
Now, suppose that
. Now the sign of the expression is flipped by the absolute value, and the equation becomes

Again, the solution is coherent with the assumption, so we can accept this value as well.