How would you interpret the number of sars deaths as an area under a curve?

Is the ordered pair (0, 4) a solution of the inequality y≤x−3? Explain.

Andrew [12]

The ordered pair (0,4) does not satisfy the inequality thus, it will be not the solution to the given inequality.

<h3>What is inequality?</h3>

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

As per the given inequality,

y ≤ x - 3

Put x = 0

y ≤ 0 - 3

y ≤ -3

Since 4 ≤ -3 is the wrong statement thus it will not satisfy the inequality.

Hence "The ordered pair (0,4) does not satisfy the inequality thus, it will be not the solution to the given inequality".

For more about inequality,

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4 0

1 year ago

Read 2 more answers

Describe the transformation done to y=1/x to get y=1/4x-12.<br><br> Please Show Work.

goldenfox [79]

These are the steps for transforming y=1/x to y=1/4x -12:

Step 1: Compress the original function by 4 in x direction. This will yield,

y= 1/4x

Step 2: The resulting function in step 1 is moved down by 12 spaces. The resulting function will be;

y= 1/4x -12

3 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$