you just got free tickets to go on the boat ride and you can bring 3 friends unfortunately you have 5 friends who want to come a
long how many different groups can you take with you
1 answer:
Assuming that your own ticket is already secured.
From the 5 friends you can only choose 3.
The order in which these friends are chosen is not relevant. So this is a Combination problem.
Where the order is relevant the problem becomes a Permutation problem!
So the answer is 5 combination 3. = ⁵C₃
⁵C₃ = (5 * 4 * 3) / ( 3 * 2 * 1) = 10
You can take 10 groups of any 3 of your 5 friends.
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