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3 years ago

Awnser me pkeaeeeeeeeeee

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Answer:

46.01

Step-by-step explanation:

i.e sum of all the purchases + 7% of the total purchase.

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If A, B, and C are collinear, and AB = 18, AC = 41, what is a possible measure of BC?

ikadub [295]

Step-by-step explanation:

As ANC are collinear,

AB+BC=AC

so,

18+BC = 41

BC = 41-18

BC = 23 is the answer.

8 0

3 years ago

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The product of two consecutive integers is 420 which quadratic equation can be used to find x the lesser number

Fynjy0 [20]

Answer:

Step-by-step explanation:

If the smallest number is 'x', then the other number = x +1

x*(x+1)= 420

Use distributive property

x*x + x*1 = 420

x² + x - 420 =0 ------> this is the required quadratic equation.

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3 years ago

Find the measure of <2.

iVinArrow [24]

Should be 30 as well

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3 years ago

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Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

Please help!!! (With one or all the problems, anything is greatly appreciated if you understand probability)

professor190 [17]

Here are the answers to problem 1..

a) 11

b) 5/36

c) 25 Times because 7 has a probability of 16.667%

d) 25 Times because 10, 11, and 12 have a probability sum of 16.667% ironically...

Hope this helps. :)

6 0

3 years ago