Area would be 4.52 A= pi x radius squared
Circumference would be 7.54 C= 2 pi radius. Hope that makes sense.
Answer:
23 2/5
Step-by-step explanation:
convert mixed numbers to improper fractions: 1 3/10=13/10
13/10*18
convert element to fraction: 18=18/1
=18/1*13/10
cross cancel common factor:2
=13/5*9/1
multiply fractions
=13*9/5*1
=117/5
convert improper fraction to mixed numbers
23 2/5
The description below proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
<h3>How to prove an Isosceles Triangle?</h3>
Let ABC be an isosceles triangle such that AB = AC.
Let AD be the bisector of ∠A.
We want to prove that BD=DC
In △ABD & △ACD
AB = AC(Thus, △ABC is an isosceles triangle)
∠BAD =∠CAD(Because AD is the bisector of ∠A)
AD = AD(Common sides)
By SAS Congruency, we have;
△ABD ≅ △ACD
By corresponding parts of congruent triangles, we can say that; BD=DC
Thus, this proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
Read more about Isosceles Triangle at; brainly.com/question/1475130
#SPJ1
Answer:
x= -5
Step-by-step explanation:
2x=-13-3
2x=-10
x=-5
As it is shown in the figure, the length of the square's side s is also the length of the circle's diameter d:
s = d = 28 in.
• Computing the area of the square:
A₁ = s²
A₁ = 28²
A₁ = 28 × 28
A₁ = 784 in² ✔
• Computing the area of the circle:
A₂ = π × r²
A₂ = π × (d/2)²
A₂ = π × (28/2)²
A₂ = π × 14²
A₂ ≈ 3.14 × 14 × 14
A₂ ≈ 615.44 in² ✔
—————
• The area of the shaded portion is equal to the difference between the area of the square and the area of circle:
A = A₁ – A₂
A ≈ 784 – 615.44
A ≈ 168.56 in² <——— this is the answer (1st option).
I hope this helps. =)
