Answer:
90°
Step-by-step explanation:
Given - Mariyam wants to cut her chocolate brownie into two rectangles.
To find - What kind of angles will Mariyam form?
Proof -
If she cut the brownie in the rectangular shape, then the angle formed is 90°.
Answer:
value if a =

Step-by-step explanation:
here's the solution :-
=》
![\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%28%5Csqrt%7Bm%7D%29%20%20%7B%7D%5E%7B3%7D%20%7D%7B%20%5Csqrt%5B4%5D%7Bm%7D%20%7D%20)
=》

=》

=》

=》

=》

so, a = 5/4
Answer:
x= 21
y= 3
z= 21
Step-by-step explanation:
Let the center be O,
=> Triangle AOD is an Isosceles triangle so AO≅DO, "21 = x"
=> Line AC is divided in two equal parts by the center so if AO= 21 then
7y = 21, and thus "y = 3"
=> BOC is also an Isosceles triangle so CO ≅ BO, if CO = 21 (7y → 7*3) then so will be BO. Therefore "z = 21"
<h2>Greetings!</h2><h3>A way to do this is to divide the actual amount by the predicted amount:</h3>
8206 ÷ 13,426 = 0.6112
<h3>To change this back into a percentage simply multiply by 100:</h3>
0.6112 x 100 = 61.1
<h3>So the percent of voter turn out was 61.1%</h3><h2>Hope this helps!</h2>