Answer:
Step-by-step explanation:
Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.
2p - 3q = 4 ...................... 1 * 3
3p + 2q = 9 ..................... 2 * 2
Multiplying equation 1 by 3 and 3 by 2:
6p - 9q = 12
6p + 4q = 18
Subtracting both equation
-9q-4q = 12-18
-13q = -6
q = -6/-13
q = 6/13
Substituting q = 6/13 into equation 2
2p - 3(6/13) = 4
2p - 18/13 = 4
2p = 4+18/13
2p = (52+18)/13
2p = 70/13
p = 70/26
p = 35/13
<em>Hence p = 35/13 and q = 6/13</em>
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<em>b) </em>If if 223ₓ = 87 find x
Using the number base system and converting 223ₓ to base 2 will give us;
223ₓ = 2*x² + 2*x¹ + 3*x⁰
223ₓ = 2x²+2x+3
Substituting back into the equation, 2x²+2x+3 = 87
2x²+2x+3-87 = 0
2x²+2x-84 = 0
x²+x-42 = 0
On factorizing:
(x²+6x)-(7x-42) = 0
x(x+6)-7(x+6) = 0
(x+6)(x-7) = 0
x+6 = 0 and x-7 = 0
x = -6 and 7
<em>Hence the value of x is 7 (neglecting the negative value)</em>
Three Times Two Equals Six or Two Times Three Equals Six
Six Times One Equals Six
The original function is
f(x)=√x
As this is condition for √x function, x≥ 0
So,
Domain= [0, infinity)
Range= [0, infinity)
After the reflection across x-axis and y-axis, we get a function,
g(x)=-√-x
-x≥ 0 means x≤ 0,
So,
Domain= (-infinity, 0]
Range= (-infinity, 0]
From this you can see that
-The only value that is in the domains of both functions is 0.
-The range of g(x) is all values less than or equal to 0.
only these points are correct and all other points are wrong.
See the attached graphs for both functions.
Answer: hvdwc bc3uich3jbf 3ichb3lfbd3piujbvler
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Step-by-step explanation:
Answer:
Step-by-step explanation:
all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction
