Ask question

Ask question

All categories

3 years ago

6

What is the

n="absmiddle" class="latex-formula"> as a fraction?

1 answer:

zvonat [6]3 years ago

4 0

The answer you want will be 1.91293\dots

You might be interested in

First to answer gets brainliest and five stars

puteri [66]

Answer:

A=5 B=4
volume = 88

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In this exercise, we estimate the rate at which the total personal income is rising in the Richmond-Petersburg, Virginia, metrop

lyudmila [28]

Answer:

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year

Step-by-step explanation:

Let $t$ be the number of years after 1999.

From the information given:

In 1999, the population in this area was 961400, and the population was increasing at roughly 9200 people per year.
The average annual income was 30593 dollars per capita, and this average was increasing at about 1400 dollars per year.

The population growth can be modeled with a linear equation. The initial population was $P_0$ is 961400 and it grows by 9200 people per year.

The population in time t can be written

$P(t)=9200t+961400$

The average annual income can be modeled with a linear equation. The initial average annual income was 30593 dollars per capita and it grows by 1400 dollars per year.

$A(t)=1400t+30593$

If we multiply both together gives the total personal income at time t.

$T(t)=P(t)\cdot A(t)\\T(t)=(9200t+961400)\cdot (1400t+30593)$

The rate at which the total personal income was rising in the Richmond-Petersburg area is the derivative $T(t)'$

We need to use the Product Rule that says

If f and g are both differentiable, then:

$\frac{d}{dx}[f(x)g(x)]=f(x)\frac{d}{dx}[g(x)] +g(x)\frac{d}{dx}[f(x)]$

Applying the Product Rule

$\frac{d}{dt}T(t)=\frac{d}{dt} [(9200t+961400)\cdot (1400t+30593)]\\\\T(t)'=\frac{d}{dt}\left(9200t+961400\right)\left(1400t+30593\right)+\frac{d}{dt}\left(1400t+30593\right)\left(9200t+961400\right)\\\\T(t)'=9200\left(1400t+30593\right)+1400\left(9200t+961400\right)\\\\T(t)'=12880000t+281455600+12880000t+1345960000\\\\T(t)'=25760000t+1627415600$

For 1999, t = 0.

The raising is

$T(0)'=25760000(0)+1627415600\\T(0)'=1,627,415,600$

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year.

7 0

3 years ago

3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo

salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And if we replace the values obtained we got this:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

6 0

3 years ago

20 POINTS!!! PLEASE HELP

pogonyaev

The logarithm of 10 to base 10 is 1

<h3>How to determine the logarithm?</h3>

The given parameters are:

Base = 10
Number = 10

So, the logarithm expression can be represented as:

$\log_{10}10$

The law of logarithm states that:

$\log_{x}x = 1$

The above means that;

When the base and the number are the same, the logarithm is 1

So, we have:

$\log_{10}10 = 1$

Hence, the logarithmic value is 1

Read more about logarithm at:

brainly.com/question/20785664

#SPJ1

7 0

2 years ago

What is 1 7/16 as a decimal?

klasskru [66]

$1.4375$
these words are too meet the 20 character minimum

5 0

3 years ago

Read 2 more answers