Given inequalities are
and
Now we will graph both inequalities to get the common region which represents solution.
<u>Work for </u>
first we graph the line x+y=4 then shade the graph for inequality symbol 
we can plug any random number for x and find y-value to get points
lets plug x=0 then we get:
x+y=4
0+y=4
y=4
so the point is (0,4)
Similarly we can find more point like (4,0).
Now graph both points and join both points by straight line.
Now we find direction of shading.
pick any test point which is not on that line x+y=4 say (0,0)
and plug it into orinal inequality
which is true.
True means shade in direction of test point. Otherwise we shade in opposite direction.
We will repeat same process for other inequality to graph that.
Hence final graph for the answer will be as shown in attached image.
Triangular region ABC is final answer.
The necessary information regarding this problem is already given. Based on this information, the answer can be easily deduced.
236.5 ml = 1 cup
Then
1080 ml = 1080/236.5
= 4.56 cups
= 4 1/2 cups approx
From the above deduction we can conclude that the number of cups required for making the recipe is about 4 1/2 cups. I hope that this is the answer that has actually come to your desired help.
9.4 - 1.8 will tell you the distance between them
(36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8"
This is the equation that you would get for the average. Now we just solve for z.
Following PEMDAS you have to mulitply the equation by 4 to get rid of the divide by 4 part.
4( (36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8)
Which does this
36 3/4" + 36 3/8" + 371/2" +z = 146 1/2"
Now you have to add and subtract to get "z" by itself.
36 3/4" + 36 3/8" + 371/2" = 110 5/8"
(110 5/8" + z = 146 1/2" ) -110 5/8"
z= 35 7/8", so the answer is b
I think your asking how much the school will have left over. If so:
125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.
You didn't word this properly so that what I got with what I had:)
If you have anymore questions, ask me them on my profile so I'll be sure to get them:)
I hope this helps:)
