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UkoKoshka [18]
3 years ago
9

Right in equation of the ellipse The rest of the question is in the photo

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

1) The vertices are (-5 , 0) and (5 , 0)

  The co-vertices are (0 , -2) and (0 , 2)

  The foci are (-√21 , 0) and (√21 , 0)

2) The equation of the ellipse ⇒ x²/48 + y²/64 = 1

Step-by-step explanation:

1) ∵ 4x² + 25y² = 100 ⇒ ÷ 100

∴ x²/25 + y²/4 = 1

∵ The standard equation of the ellipse with center (0 , 0) is

   x²/a² + y²/b² = 1

∴ a² = 25 ⇒ ∴ a = ±5

∴ The vertices are (-5 , 0) and (5 , 0)

∴ b² = 4 ⇒ ∴ b = ±2

∴ The co-vertices are (0 , -2) and (0 , 2)

∵ c² = a² - b²

∴ c² = 25 - 4 = 21

∴ c = ±√21

∴ The foci are (-√21 , 0) and (√21 , 0)

2) ∵ Its center is (0 , 0)

∵ The vertex of it is (0 , -8)

∴ a² = 64

∵ The focus is (0 , 4)

∴ c² = 16

∵ c² = a² - b²

∴ b² = a² - c² = 64 - 16 = 48

∵ b² = 48

The standard equation of the ellipse with center (0 , 0) is

   x²/b² + y²/a² = 1 ⇒ major axis // to y-axis

∴ x²/48 + y²/64 = 1

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Doug’s family buys 7 postcards while on vacation. Each postcard costs 0.25$ including tax. How can Doug use the number line to f
larisa [96]

Answer: Total cost is $1.75

Explanation:

Since we have given that

Number of postcards bought by Doug's family= 7

Cost of each postcard including tax = $0.25

Total cost is given by

7\times 0.25=\$1.75

Now, we want to show this in number line :

On the number line put all the number with a difference of 0.25 and run the number line seven times and we get the answer.

Each step is of length 0.25 and there are 7 jumps to reach required answer.

So, after 7 jumps we reach at 1.75 which is the required answer.

Hence total cost is $1.75

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3 years ago
How can you find the sum of the angle measures in a triangle?
sattari [20]

Answer:

a Euclidean space, the sum of angles of a triangle equals the straight angle (180 degrees, π radians, two right angles, or a half-turn). A triangle has three angles, one at each vertex, bounded by a pair of adjacent sides.

8 0
3 years ago
A car insurance company has high-risk, medium-risk, and low-risk clients, who have, respectively, probabilities .04, .02, and .0
Paha777 [63]

Answer:

(a) 0.983

(b) 0.353 or 35.3%

(c) 0.604 or 60.4%

Step-by-step explanation:

a) The probability of a random client does not file a claim is equal to the sum of:

1) the probability of a client being high risk and does not file a claim = P(hr)*(1-P(c_hr))

2) the probability of a client being medium risk and does not file a claim = P(mr)*(1-P(c_mr))

and

3) the probability of a client being low risk and does not file a claim = P(lr)*(1-P(c_lr))

P(not claim) = P(hr)*(1-P(c_hr))+P(mr)*(1-P(c_mr))+P(lr)*(1-P(c_lr))

P(not claim) = 0.15*(1-0.04)+0.25*(1-0.02)+0.6*(1-0.01)

P(not claim) = 0.15*0.96+0.25*0.98+0.6*0.99 = 0.983

(b) To know the proportion of claims that come from high risk clients we need to know the total expected claims in every category:

Claims expected by high risk clients = P(c_hr)*P(hr) = 0.04*0.15 = 0.006 claims/client

Claims expected by medium risk clients = P(c_mr)*P(mr) = 0.02*0.25 = 0.005 claims/client

Claims expected by low risk clients = P(c_lr)*P(lr) = 0.01*0.60 = 0.006 claims/client

The proportion of claims done by high risk clients is

Claims by HR clients / Total claims expected = 0.006 / (0.006+0.005+0.006) =  0.006 / 0.017 = 0.3529 or 35,3%

(c)  The probability of being a client of a particular category and who don't file a claim is:

1) High risk: 0.15*(1-0.04) = 0.144

2) Medium risk: 0.25*(1-0.02) =  0.245

3) Low risk: 0.6*(1-0.01) = 0.594

The probability that a random client who didn't file a claim is low- risk can be calculated as:

Probability of being low risk and don't file a claim / Probability of not filing a claim

P(LR&not claim)/P(not claim) = 0.594 / (0.144+0.245+0.594)

P(LR&not claim)/P(not claim) = 0.594 /  0.983 = 0.604 or 60.4%

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Where r u from?
.,.,.?.?.?.?.?.?.?.,…..
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Answer:

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Step-by-step explanation:

This is the answer I know. let me know if I'm wrong

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