Question

Find the point, M, that divides segment AB into a ratio of 3:1 if A is at (-4, -2) and B is at (4, -10).

Answer 1

the point, M, that divides segment AB into a ratio of 3:1

A is at (-4, -2) and B is at (4, -10).

Apply section formula

$(\frac{mx_2 + nx_1}{m+n} , \frac{my_2 + ny_1}{m+n})$

Here m,n is the ratio

m =3, n= 1

A is (-4,-2) that is (x1,y1)

B is at (4, -10) that is (x2,y2)

plug in all the values in the formula

$(\frac{3(4) + 1(-4)}{3+1} ,\frac{3(-10) + 1(-2)}{3+1})$

$(\frac{8}{4} ,\frac{-32}{4})$

(2, -8)

Point M is (2,-9)

Answer 2

Answer:

ANSWER CHOICE D.

Step-by-step explanation: