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goldfiish [28.3K]
3 years ago
15

Bangun persegi 1 dan 23 cm dan 12 cmPerbandingan luas kedua persegi tersebut adalah....​

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer: hey since you are taking away points from people and being mean imma do the same:))) hope ur day is s(!t:)

Step-by-step explanation:

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320÷÷((11−9)32(11−9)32) x 8 =
jarptica [38.1K]

320÷((11−9)32(11−9)32) x 8

320÷((352-288)(352-288) x 8

320÷(64 x 64) x 8

320÷4096 x 8

0.078125 x 8

0.625

Answer:0.625

3 0
2 years ago
please can someone smart help me,please do not answer if you dont know the answer,also answer all these questions please:).
yarga [219]

Answer:

Number 7: 22.10 divided by 2.6 = 8.5  or 8.50 (depending on what your teacher prefers.

Step-by-step explanation:

Not sure about question 2 or 10

8 0
3 years ago
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
The speed of a bus from University A to University B was decreased by 20% to 48 miles per hour. What was the speed of the bus be
Lunna [17]

Answer:

initial speed: 240 m/h

Step-by-step explanation:

48 m/h is the current speed which is the 20% of X

x (20 / 100) = 48

20x = 4800

x = 4800/20

x = 240 m/h

5 0
2 years ago
If the mean, median and mode of a distribution are 5, 6, 7 respectively, then the distribution is:
QveST [7]
<span>the distribution is 43

</span>
3 0
3 years ago
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