Answer:
9
Step-by-step explanation:
f(x) = 2x+9
f(x) = 27
so, you get:
2x+9=27
2x=18
x=9
Answer:
P = 3.6 + 6 + 3.6 + 6 = 19.2 units
Step-by-step explanation:
distance between (-3,-2) and (-5,-5) =
Sqrt[(-5-3)^2+(-5 - -2)^2]
Sqrt (4+9) = 3.6
d = (-5,-5) and (1,-5) =
Sqrt[(1 - - 5)^2 + (-5 - - 5)^2]
= sqrt (36 + 0) = 6
d = (1,5) and (3,-2)
Sqrt[(1 - - 3)^2 + (-5 - - 2)^2]
Sqrt(4+9) = 3.6
d = (3,-2) and (-3,-2)
Sqrt[(-3-3)^2 + (-2 - - 2)^2]
Sqrt (36+0) = 6
11/3 divides by 60/11 = 660/33 = 20
I'm not really sure what you're asking, but if you want to calculate the first two terms of the sequence after a1, then here's the answer:
If a1=2, then a2 = -3(a1 - 1)^2 = -3(2-1)^2 = -3*(-1)^2 = -3*1 = -3.
Then, a3 = -3(a2 - 1)^2 = -3(-3-1)^2 = -3(-4)^2 = -3*16 = -48.
I'm sorry if this is not what you wanted.
If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem,
and
. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
