Answer:
At the point where x = 2.
Step-by-step explanation:
First find the derivative which gives us the gradient of the tangent at any point on the curve:
y = 5x^2 - 16x
y' = 5*2 x^(2-1) - 16 x(1-1)
y' = 10x - 16.
y' is the gradient at point of coordinate x.
So when the gradient = 4:
4 = 10x - 16
10x = 20
x = 2.
first, lets distribute the equation. 5(n^2+n)-3n(2n^2+4n-2) would become
5n^2 +5n -6n^3 -12n^2 +6n
Now we add the like terms.
-6n^3 - 7n^2 +11n
I think the correct answer should be 1/8 or 1:8
Answer:
Answer:
tha answer is d .
Step-by-step explanation:
i did this test
Step-by-step explanation:
