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4 years ago

Solve for x,,,3x-1/4=-5/11

1 answer:

4 0

$\dfrac{3x-1}{4}=-\dfrac{5}{11}\ \ \ \ |cross\ multiply\\\\11(3x-1)=4\cdot(-5)\\\\33x-11=-20\ \ \ \ |add\ 11\ to\ both\ sides\\\\33x=-9\ \ \ \ |divide\ both\ sides\ by\ 33\\\\x=-\dfrac{9}{33}\\\\\boxed{x=-\dfrac{3}{11}}$

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Y varies inversely with x. When x = 3 then y = 5. Write a function to represent this relationship.

Mariulka [41]

Answer:

<em>The function to represent this relationship will be: $y= \frac{15}{x}$ </em>

Step-by-step explanation:

$y$ varies inversely with $x$ . That means......

$y= \frac{k}{x}..............................(1)$

where $k$ is a proportional constant.

Given that, when $x=3$ , then $y=5$

Plugging these values into the above equation, we will get.....

$5=\frac{k}{3}\\ \\ 5(3)=\frac{k}{3}(3)\\ \\ 15=k$

Now plugging this $k=15$ into equation (1).....

$y= \frac{15}{x}$

So, the function to represent this relationship will be: $y= \frac{15}{x}$

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4 years ago

Find the area of the triangle. PLEASE HELP!

sladkih [1.3K]

Answer:

A = BxH/2

Step-by-step explanation:

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3 years ago

Never Mind, I figured it out already

FrozenT [24]

Figured what out
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5 0

3 years ago

Read 2 more answers

What's the answer - 0.5(4x - 5) > 7 Pls.

jeka57 [31]

Answer:

-2x+2.5 > 7

Step-by-step explanation:

Im not sure what you mean by the answer because there are no answer choices so i jus simplified for you

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3 years ago

How do I find out these arc measures?

yawa3891 [41]

Angle SUR and PUQ are vertical angles and both = 42°

Line QS is a diameter and so angle PUQ + PTU + TUS = 180°

42° + 64° + angle TUS = 180° Therfore, angle TUS = 74°

Angle QUR + SUR = 180°. Therefore, angle QUR = 138°

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4 years ago