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Hunter-Best [27]

2 years ago

8

What is 1+1 i need help hurry

1 answer:

Maru [420]2 years ago

7 0

Answer:

2

Step-by-step explanation:

just add them common sense just saying!!

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A cube has a volume of 512 mm^3. If all sides of the cube are divided by 4, what will the resulting volume be?

pshichka [43]

$\bf \textit{volume of a cube}\\\\
V=s^3\qquad \boxed{s=\frac{s}{4}}\implies V=\left( \cfrac{s}{4} \right)^3\implies V=\cfrac{s^3}{4^3}\implies V=s^3\cdot \cfrac{1}{4^3}
\\\\\\
V=s^3\cdot \cfrac{1}{64}\impliedby \frac{1}{64}\textit{ of the original volume, if the original was 512}
\\\\\\
512\cdot \cfrac{1}{64}\implies \cfrac{512}{64}$

3 0

2 years ago

A video game has 25 levels. At level one, a player has 5 points. Each additional level increases the player's points by 10. If

ozzi

Answer:

<u>B. (3,25)</u>

Step-by-step explanation:

x = level of the video game

y = number of points

At level 1, a player has 5 points.

At level 2, the player has 5 + 10 = 15 points

Therefore, we can use the function notation this way:

f(x) = 5x + 10

<u>The only ordered pair given that is from this function is:</u>

<u>B. (3,25)</u>

<u>f(3) = 5 * 3 + 10 </u>

<u>f(3) = 15 + 10 = 25</u>

The remaining three don't represent this function.

3 0

3 years ago

What are the roots of the equation x^2+4x-5=f(x)

enyata [817]

Answer:

The roots are -5, 1.

Step-by-step explanation:

$f(x) = x^2 + 4x - 5$

The roots of a function are also the Ox intercepts, so basically we're finding when is the function equal to '0'.

$x^2 + 4x - 5 = 0\\(x-1)(x+5) = 0\\x_1 = 1, x_2 = -5$

3 0

2 years ago

The diameter of a circle is 3 meters. What is the circumference?

Gennadij [26K]

Answer:

C≈9.42m

Using any of this formulas

C=2πr

C=2πrd=2r

Solution:

C=πd=π·3≈9.42478m

3 0

2 years ago

Which statements are true?<br>(look at picture)

Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

A

$n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)$

this is <u>not</u> an odd number

B

$n(n-1)=(2a+1)2a$

this is <u>not</u> an odd number

C

$(n-1)^2=(2a+1-1)^2=4a^2$

this is <u>not</u> an odd number

D

$n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1$

so this is an odd number

E

$n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1$

so this is an odd number

F

$(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1$

this is an odd number

hope this helps

7 0

2 years ago