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Marina CMI [18]
3 years ago
7

Use an associative property to complete the statement. (bc)*a

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
I don’t get what it is asking
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Which of the following is a multiple of 5<br><br> A.235<br> B. 532<br> C.17<br> D. 48
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Will give brainliest to 1st
Alecsey [184]

Answer:

x=10.5

Step-by-step explanation:

5(x+3)=(6)(12)-[.5(6)(12-x)]

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x=10.5

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3 years ago
Consider the following hypothesis test:H 0: = 17H a: 17A sample of 40 provided a sample mean of 14.12. The population standard d
Nonamiya [84]

Answer:

We conclude that the population mean is not equal to 17.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 17

Sample mean, \bar{x} = 14.12

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 4

First, we design the null and the alternate hypothesis

H_{0}: \mu = 17\\H_A: \mu \neq 17

We use Two-tailed z test to perform this hypothesis.

a) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{14.12 - 17}{\frac{4}{\sqrt{40}} } = -4.5536

b) P-value can be calculated from the standard z-table.

P-value = 0.0000

c) Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17

d) Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

e) Rejection Rule:

We reject the null hypothesis if it is less than lower critical value and greater than the upper critical value

If the z-statistic lies outside the acceptance region which is from -1.96 to +1.96, we reject the null hypothesis.

f) Since the calculated z-stat lies outside the acceptance region, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17.

4 0
3 years ago
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