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Olin [163]
3 years ago
5

Plz help!!! Will give brainliest!!!

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

94+41=135.

180-135=45.

45+111=156

180-156=24

x=24.

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-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
Use the arc length formula and the given information to find r. s = 12 cm, 0 = 360; r = ?
hjlf
use s=r0

but first convert 360 degree to radian
you will get 6.284 radian

then you substitute and get the answer!

12= r (6.284)
r= 1.91 cm
8 0
2 years ago
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