The expression 4•4•4•4•4•4 can be expressed as 4^5 6^4 5^4 4^6

Which of the following is not a typical characteristic of a linear programming problem?

adell [148]

The answer is c. The problem can be solved graphically

6 0

3 years ago

Sawyer recorded the number of different types of pets his friends have in the table shown below:

Colt1911 [192]

The answer to your question is "A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 2 crosses, Dog has 3 crosses, Rabbit has 1 cross, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners." Because this is the only plot described that fits with the data from the table with the information on how many cats, dogs, rabbits, and guinea pigs there are.

8 0

3 years ago

Read 2 more answers

(-2, 11) & (5,6) What is the slope of the equation between these two points?

ololo11 [35]

Answer:

$m =\dfrac{-5}{7}$

Step-by-step explanation:

Given :-

Two points (-2,11) and (5,6) .

And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,

$\implies Slope (m) =\dfrac{ y_2-y_1}{x_2-x_1}$

Here the two points are (-2,11) and (5,6) .So put on the respective values ,

$\implies Slope (m) =\dfrac{ 11 - 6}{-2-5}\\\\\implies Slope = \dfrac{5}{-7} \\\\\implies Slope = \dfrac{-5}{7}$

Hence the slope of the line is -5/7 .

8 0

2 years ago

For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

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The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

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Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

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$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

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Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

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Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

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The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

2 years ago

Which equation is equivalent to the equation 6x+9=12? A: x + 9 = 6 B: 2 x + 3 = 4 C: 3 x + 9 = 6 D: 6 x + 12 = 9

Pachacha [2.7K]

Answer: B

Step-by-step explanation:

3 0

2 years ago