Answer:
the answer to your question is A
Step-by-step explanation:
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
y=x+1
Step-by-step explanation:
Rise over run. The line starts positive one and goes up one and over one.
Hope this helps!
Your answer would be 23.85 but I presume they rounded up so it would be 23.9
