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3 years ago

5

A tip employee’s earnings most closely resemble those of which of the following? a. An employee working on straight commission b

. An employee working on commission plus salary c. An employee working on a piece-rate basis d. An employee working on a fixed salary

2 answers:

rosijanka [135]3 years ago

8 0

Answer:

c

Step-by-step explanation:

Lelechka [254]3 years ago

6 0

Your answer would be C

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Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

8 0

3 years ago

a un baile asistieron 270 personas.si los boletos de costaban 100 pesos y los de dama 80 pesos y se recaudaron 24 800 pesos por

ser-zykov [4K]

The question in English
<span>A dance was attended by 270 people. If the gentlemen tickets cost 100 pesos and the lady tickets 80 pesos and 24800 pesos were collected for all the tickets. How many women and how many men attended the dance?

let
x---------> the number of men
y--------> the number of women

we know that
x+y=270----> x=270-y-----> equation 1
100x+80y=24800-------> equation 2
substitute equation 1 in equation 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

the answer is
the number of men ---> 160
the number of women----> 110

the answer in Spanish

</span>hagamos
x--------->la cantidad de hombres
y--------->la cantidad de mujeres

Sabemos que
x+y=270----> x=270-y-----> ecuacion 1
100x+80y=24800-------> ecuacion 2
sustituimos la ecuacion 1 en la ecuacion 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

La respuesta es
la cantidad de hombres es 160
la cantidad de mujeres es 110

4 0

3 years ago

Solve the system by graphing:<br> y = x^3 - 4x^2 + x + 3<br> y = 2x - 1

zvonat [6]

Answer:

(-1, -3) and (1, 1)

Step-by-step explanation:

Use a graphing calculator to graph out both lines:

(See picture)

Both lines intersect at points (-1, -3) and (1, 1). These are the solutions for the system of equations.

5 0

2 years ago

Let a represent the number of ounces of perfume A. Let b represent the number of ounces of perfume B. Perfume A costs $11 per ou

Julli [10]

Answer:

The system of equations in standard form is equal to

$11a+19b=71$

$a+b=5$

The number of ounces of perfume A is $3\ ounces$

The number of ounces of perfume B is $2\ ounces$

Step-by-step explanation:

Let

a-----> the number of ounces of perfume A

b----> the number of ounces of perfume B

we know that

$11a+19b=71$ -----> equation A

$a+b=5$

$a=5-b$ -----> equation B

substitute equation B in equation A and solve for b

$11(5-b)+19b=71$

$55-11b+19b=71$

$8b=71-55$

$8b=16$

$b=2\ ounces$

Find the value of a

$a=5-b$ -----> $a=5-2=3\ ounces$

8 0

3 years ago

Read 2 more answers

( 2 7/8 + 3 3/8 ) + 1 1/8 =

Monica [59]

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5 0

3 years ago