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Alina [70]
3 years ago
12

Factor the polynomial 16b^4+30b^3-12b^2

Mathematics
1 answer:
Lelu [443]3 years ago
4 0

Answer:

2b²(8b²+15b-6)

Step-by-step explanation:

16b^{4}+30b³-12b²

2b²(8b²+15b-6)

This is not further factorable. If you want to find the roots, you'd have to use the quadratic formula for the polynomial in the parentheses. Therefore that is our final answer.

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Irina-Kira [14]

Answer:

The sin A expressed in ratio form is \frac{\sqrt{6} }{4}

Step-by-step explanation:

From the given right angled triangle diagram, sin A is calculated as follows;

sin \ A = \frac{Opp}{hypo} \\\\sin \ A = \frac{2\sqrt{6} }{8} \\\\sin \ A = \frac{\sqrt{6} }{4}

Therefore, the sin A expressed in ratio form is \frac{\sqrt{6} }{4}

3 0
3 years ago
Help me with number 5 please
drek231 [11]

Answer:

17.95

Step-by-step explanation:

You subtract 964.36 from 982.31

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4 years ago
Identify the values of the variables. Give your answers in simplest radical form. HELP PLEASE!!!
galben [10]

Answer:

x = 3\sqrt{2}

y = 6\sqrt{2}

Step-by-step explanation:

The triangle is a 30-60-90 right triangle.

The ratio of the lengths of the sides is:

1 : \sqrt{3} : 2

The order of the sides in the ratio above is

short leg : long leg : hypotenuse

The long leg is sqrt(3) times the length of the short leg.

x \times \sqrt{3} = 3\sqrt{6}

x = \dfrac{3\sqrt{6}}{\sqrt{3}}

x = 3 \times \sqrt{\dfrac{6}{3}}

x = 3\sqrt{2}

The hypotenuse is twice the length of the short leg.

y = 2 \times 3\sqrt{2}

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6 0
3 years ago
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In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

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