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2 years ago

I need help someone please

Mathematics

1 answer:

Alja [10]2 years ago

4 0

Answer:

easy

Step-by-step explanation:

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Brianna has x nickels and y pennies. She has no less than 20 coins worth no more

Bond [772]

Answer:

$y \ge 20 - x$

$y \le 80 -5x$

$(x,y) = (15,5)$

Step-by-step explanation:

Given

$Nickels = x$

$Pennies = y$

$Amount = \$0.80$ maximum

$Coins = 20$ minimum

Required

Solve graphically

First, we need to determine the inequalities of the system.

For number of coins, we have:

$x\ +\ y\ge 20$ because the number of coins is not less than 20

For the worth of coins, we have:

$0.05x\ +\ 0.01y\ \le0.80$ because the worth of coins is not more than 0.80

So, we have the following equations:

$x\ +\ y\ge 20$

$0.05x\ +\ 0.01y\ \le0.80$

Make y the subject in both cases:

$y \ge 20 - x$

$0.01y \le 0.80 - 0.05x$

Divide through by 0.01

$\frac{0.01y}{0.01} \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le 80 -5x$

The resulting inequalities are:

$y \ge 20 - x$

$y \le 80 -5x$

The two inequalities are plotted on the graph as shown in the attachment.

$y \ge 20 - x$ --- Blue

$y \ge 80 -5x$ --- Green

Point A on the attachment are possible solutions

At A:

$(x,y) = (15,5)$

4 0

2 years ago

Points (-5,-3) (-2,-2) (-4,-6) reflected over y=-x-1

Mars2501 [29]

Answer:

frfrfr

Step-by-step explanation:

8 0

2 years ago

If the supplement angle is 12 degrees less tan twice the measure of the angle,what is the measure of the angle

pentagon [3]

x = 2(180 - x) - 12

3x = 348

x = 116

The measure of the angle is 116 degrees.

6 0

3 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

Which graph shows a rate of change of 1/2 which is a fraction between –4 and 0 on the x-axis?

irakobra [83]

By definition, we have that the average rate of change is given by:

$AVR = \frac{y2-y1}{x2-x1}$