Answer: There will be no effect on the protein produced
Explanation:
According to the genetic code, the triplet codon GAG code for the amino acid, glutamate, while GAC code for aspartate.
Since GAG and GAC code for amino acids with similar properties (aspartate and glutamate are both acidic amino acids due to the extra carboxyl group present in their side chain), the change in nucleotide is still similar to the original, so will result in a different amino acid sequence, but will not alter the function of the protein at all. Thus, this kind of mutation is called silent mutation.
Answer:
b.Grow and change
c.Have a complex chemistry
d.Maintain homeostasis
Explanation:
Answer:
The catalyst would be the tablets.
Explanation:
The tablets start the reaction. That is what catalysts do.
Answer:
Function will be disrupted by adding the urea and regained by removing the urea.
Explanation:
The protein is one of the important biomolecule made of the polymers of the alpha amino acids that are linked together by peptide bonds. The protein works at their specific pH.
Denaturants disrupt the 3 dimensional structure of protein that affect their normal functioning. In the given experiment, the urea acts as denaturant and disrupt the protein structure. The removal of urea will reverse the denaturant condition and protein gain its function.
Thus, the correct answer is option (a).
Answer:
I think the question is "How might an RNA-based genome results display an increased in infection rate?" because current statement doesn't convey a message clearly.
Explanation:
To answer this question, we need to understand first that what is gene expression. Gene expression is a process in which genetic information is transcribed first to RNA and then into proteins. During transcription stage, only active genes would be transcribed to RNA and all other DNA material don't transcribe at all. Now, if there is an infection, host cell would express only those genes which would actively take part in the defense mechanism, e.g. R-genes, genes involved in production of reactive oxygen species, etc. Hence, to monitor the infection rate, we will look at the RNA-based genome. To do this, we will extract the total RNA and then would sequence it. Then we will annotate the genes and check the relative abundance (differential expression). Finally, we would have a clear that these genes were active against the infection. By doing temporal sampling and sequencing, we would be able to measure the rate as well.
For the second part, potential complications that could arise in doing analysis is the lower amount of RNA, or rapid degradation of RNA in case of presence of RNAses. RNA can be degraded easily at room temperature.
