Answer:
The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.
Step-by-step explanation:
Given
For any given function f(z), it is analytic and not constant throughout a domain D
To Prove
The function f(z) is non-constant constant in the neighbourhood lying in D.
Proof
1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀
2-Now consider another function F₁(z) where
F₁(z)=f(z)-ω₀
3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.
4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.
5-Replacing value of F₁(z) in the above gives:
F₁(z)≡0 in domain D
f(z)-ω₀≡0 in domain D
f(z)≡0+ω₀ in domain D
f(z)≡ω₀ in domain D
So this indicates that the value of f(z) for all values in domain D is a constant ω₀.
This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.
Answer:
625
Step-by-step explanation:
All it is saying to do is to do -5x-5x-5x-5
the answer is x is greater then -7
to find this add 4 to each side
then divide by -2.
since you divided both sides by a negative the symbol flips and you get x is greater then -7
Answer:
Trees.
Step-by-step explanation:
The houses look sturdy, and not that flammable. The trees and grass are very plentiful, so they would spread easily.
Please clarify if this wasn't what you were asking.
Answer:
2
Step-by-step explanation:
We have two points so we can find the slope
m = ( y2-y1)/(x2-x1)
= ( -11 - -1)/( 4 -9)
= (-11+1)/( 4-9)
-10/ -5
= 2