Distance to checkpoint A from starting line = 20 yards.
Then from A to B distance = 12 yards.
Let us take starting point C.
So, it would make a right triangle.
We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.
According to Pythagoras theorem:




BC = 23.32.
<h3>Therefore, 23.32 yards is the distance from Checkpoint B to the starting line.</h3>
Answer:
A=6a2
Step-by-step explanation:
Answer:
x²/2166784 +y²/2159989 = 1
Step-by-step explanation:
The relationship between the semi-axes and the eccentricity of an ellipse is ...
e = √(1 -b²/a²)
In order to write the desired equation we need to find 'b' from 'e' and 'a'.
__
<h3>semi-minor axis</h3>
Squaring the equation for eccentricity gives ...
e² = 1 -b²/a²
Solving for b², we have ...
b²/a² = 1 -e²
b² = a²(1 -e²)
<h3>ellipse equation</h3>
Using the given values, we find ...
b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989
The desired equation is ...
x²/2166784 +y²/2159989 = 1
Answer:
7/11
Step-by-step explanation: