All categories

3 years ago

The difference between a number c and 13 is −2. Equation: Solution:

Mathematics

2 answers:

Taya2010 [7]3 years ago

4 0

Answer:

c - 13 = - 2

grouping of like terms

c = -2 + 13

c = 11

slamgirl [31]3 years ago

3 0

Answer:

equation: c-13=-2

solution: c=11

Step-by-step explanation:

c-13=-2

add 13 on both sides

c-13+13=-2+13

c=11

ANSWER CHECK

substitute C for 11

11-13=-2

You might be interested in

sandra has $691.43 in her checking account how much does she have in her account after she makes on withdrawal of $327.19 and a

nordsb [41]

Answer:

576.99

Step-by-step explanation:hope this helps;)

7 0

3 years ago

I don’t understand :(

viktelen [127]

Answer:

The quotient when $x^3-4x^2-8x+8$ is divided by $x+2$ is $x^2-6x+4$ with no remainder, so x+2 is a factor of p(x).

Step-by-step explanation:

As the question suggests, there are two ways to solve this problem: long division (which can always be used to divide polynomials), and synthetic division (which can only be used when you are dividing by something of the form $(x-a)$ . In this case, we may use synthetic division, since $x+2$ is equal to $x-(-2)$ . I will use synthetic division here as it is slightly faster than long division.

The -2 on the left represents that we are dividing by x-(-2), and the rest of the numbers in the top row are the coefficients of p(x): 1, -4, -8, and 8.

The first step in synthetic division is to being down the leading coefficient of the polynomial: in this case, the 1 (as indicated in red). Now, we multiply the 1 by -2. We get -2, which we place directly below the -4.

Next, we add directly down the column, (-4 + (-2) is equal to -6), and this answer is placed in the box below. We can continue this process, getting the coefficients 1, -6, 4, and 0 in the bottom row.

This is the answer: the quotient is $x^2-6x+4$ , and the remainder is zero (which indicates that x+2 is a factor of p(x)).

Edit: long division

We may also solve this problem using long division (see the second image). The first step is to look at the leading coefficients: since $x \times x^2$ is equal to $x^3$ , the first term in the quotient will be $x^2$ . Since $x^2 \times (x+2)$ is equal to $x^3+2x^2$ , we must now subtract that from $x^3-4x^2-8x+8$ .

We repeat the same process, as shown in the image. Since we eventually get to zero, the remainder is zero, and the polynomial at the top (x^2-6x+4) is the quotient.

<em>I know this might be difficult to follow, so please comment if you have any questions.</em>

4 0

3 years ago

Main Street and Washington Avenue meet at a right angle. A large park begins at this corner. Joe's school lies at the opposite c

koban [17]

Here is my work:
Distance is 1.2 miles
:-)

3 0

3 years ago

Sara is saving her summer earnings for a $500 school trip in the fall. She has $200 in her savings account at the beginning of J

Vilka [71]

Answer:she will need around 9 weeks and she will have enuogh

Step-by-step explanation:

5 0

3 years ago

The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean

Elden [556K]

Answer:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

Step-by-step explanation:

Data given and notation

$\bar X=3.8$ represent the sample mean

$s=0.5$ represent the sample standard deviation for the sample

$n=15$ sample size

$\mu_o =4$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean weight is less than 4 ounces, the system of hypothesis would be:

Null hypothesis: $\mu \geq 68$

Alternative hypothesis: $\mu < 4$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

3 0

3 years ago