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IceJOKER [234]
3 years ago
8

What is Olun 1

mula1" title=" \frac{5}{6} - \frac{1}{4 } " alt=" \frac{5}{6} - \frac{1}{4 } " align="absmiddle" class="latex-formula">
need help​
Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer: =7/12

Step-by-step explanation:

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The classroom outside bag had 5 frisbees in it. If 25% of the outside toys are frisbees, then how many total toys are in the bag
malfutka [58]
So 25%=1/4 so technically you just do 5 times 4 since you need 4 more to have a full 4/4 or full 100% so 5 times 4 is 20 so there are 20 totals toys in the bag
8 0
1 year ago
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Vinil7 [7]

Answer:

Scales-No equal sides

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Equilateral-

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8 0
3 years ago
Find the exact value of tan(theta) for an angle (theta) with sec(theta) = 3 and with its terminal side in Quadrant I.
stiks02 [169]

Answer:

c

Step-by-step explanation:

1 + tan²theta = sec²theta

tan²theta = 3² - 1

tan²theta = 8

tan theta = sqrt(8)

Positive because Quadrant 1

sqrt(8) = sqrt(4×2) = sqrt(4)×sqrt(2)

= 2×sqrt(2)

3 0
3 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
recall that two angles are supplementary if the sum of their measure is 180. find the measures of two supplementary angles if on
aleksklad [387]

Answer:

I don't know if it's correct

but I tried

Step-by-step explanation:

let the angle be x

20+4x+x=180

20+5x=180

5x=160

x=32

5 0
3 years ago
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